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Worked Examples · Example 20

Q.Let U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} and A = {1, 3, 5, 7, 9}. Find A′

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The complement of a set is everything in the universal set that is not in the original set. Here, A′={2,4,6,8,10}A' = \{2, 4, 6, 8, 10\}.

The idea of a set complement is simple but powerful: it’s the “other half” of the universe. If UU is the universal set (the collection of all elements we care about), then A′A' (read “A complement” or “A prime”) contains every element of UU that is not in AA.

Think of it like a Venn diagram: UU is the entire rectangle, AA is one circle inside it. A′A' is everything outside that circle but still inside the rectangle. So to find A′A', you just scan through UU and pick out the numbers that are missing from AA.

Let’s do it step by step.

  1. List the universal set.

    U={1,2,3,4,5,6,7,8,9,10}U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}

  2. List the given set AA.

    A={1,3,5,7,9}A = \{1, 3, 5, 7, 9\}

  3. Identify what’s missing.

    Compare each element of UU against AA:

    • 11 is in AA → skip
    • 22 is not in AA → include
    • 33 is in AA → skip
    • 44 is not in AA → include
    • 55 is in AA → skip
    • 66 is not in AA → include
    • 77 is in AA → skip
    • 88 is not in AA → include
    • 99 is in AA → skip
    • 1010 is not in AA → include
  4. Collect the complement.

    The elements we kept are 2,4,6,8,102, 4, 6, 8, 10. So:

A′={2,4,6,8,10}A' = \{2, 4, 6, 8, 10\}

Watch out

A common mistake is to forget that the complement is defined only with respect to the given universal set UU. If UU were different, A′A' would change. Here, UU is clearly given, so we stick to it.

Tip

Notice that AA contains all the odd numbers from UU, and A′A' contains all the even numbers. That’s a neat pattern: complements often reveal a natural partition of the universal set.

✓Final answer

The complement of AA is {2,4,6,8,10}\boxed{\{2, 4, 6, 8, 10\}}.

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