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Exercise 4 · Q5

Q.A boat covers 32 km upstream and 36 km downstream in 7 hours. Also it covers 40 km upstream and 48 km downstream in 9 hours. Find the speed of the boat in still water and that of the stream.

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Substitute x=1/u, y=1/vx=1/u,\ y=1/v to linearise the two time equations, solve for upstream/downstream speeds, then get still-water and stream speeds: 1010 and 22 km/h.

Time=DistanceSpeed\text{Time} = \dfrac{\text{Distance}}{\text{Speed}}. With upstream speed uu and downstream speed vv: boat in still water =v+u2=\dfrac{v+u}{2}, stream =v−u2=\dfrac{v-u}{2}.

  1. Let u=u= upstream speed and v=v= downstream speed. From the data:

32u+36v=7,40u+48v=9.\dfrac{32}{u} + \dfrac{36}{v} = 7, \qquad \dfrac{40}{u} + \dfrac{48}{v} = 9.

  1. Put x=1u, y=1vx = \dfrac1u,\ y = \dfrac1v: 32x+36y=732x + 36y = 7 and 40x+48y=940x + 48y = 9.
  2. Eliminate xx: multiply the first by 4040 and the second by 3232:

1280x+1440y=280,1280x+1536y=288.1280x + 1440y = 280, \qquad 1280x + 1536y = 288.

  1. Subtract: 96y=8⇒y=11296y = 8 \Rightarrow y = \dfrac{1}{12}, so v=12v = 12 km/h. …

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