Q.The speed of a motor boat and that of the current of water is 36:5. The boat goes along with the current in 5 hours 10 minutes. How much time will it take to come back?
Concept understanding — Speed Current Boat Problems
Speed Current Boat Problems — A First Look
Imagine you're standing on the bank of a river that flows steadily downstream. You see a boat trying to cross. The boat's engine pushes it straight toward the opposite bank — but the river itself is moving sideways. What happens? The boat doesn't go straight across. It drifts downstream.
That's the core idea: the boat's motion is the sum of two independent motions — its own effort (relative to the water) and the water's flow (the current).
The Two Velocities
Every boat problem involves two distinct velocities:
Velocity of boat relative to water (vbw) — how fast the boat moves through still water, in whatever direction its engine points.
Velocity of water relative to ground (vw) — the speed and direction of the river current.
The boat's actual path over the ground is the vector sum:
vb=vbw+vw
This is not a guess — it's how relative motion works. The boat's engine moves it through the water, and the water itself carries everything along.
The Two Classic Problems
Note
Almost every exam problem falls into one of two types. Identify which one first.
Type 1 — Crossing the river (shortest time)
You point the boat straight across, perpendicular to the current. The boat's own velocity is entirely across the river. The current pushes it downstream. The time to cross depends only on the boat's speed across and the river's width — the current does not affect how long it takes, only where it lands.
Time to cross:
t=vbwcosθwidth of river
If you point straight across (θ=0), then t=vbwd.
Type 2 — Crossing the river (shortest path)
You want to land exactly opposite your starting point. To cancel the drift, you must point the boat upstream at an angle, so that the upstream component of the boat's velocity exactly cancels the current. Then the net velocity is straight across.
Condition for no drift:
vbwsinθ=vw
where θ is the angle the boat makes with the perpendicular to the bank.
A Concrete Example
A river 100 m wide flows at 3 m/s. A boat can do 5 m/s in still water. …
Downstream and upstream speeds are 36+5 and 36−5 in ratio units; for equal distance, time is inversely proportional to speed, giving a return time of 6 h 50 min.
For a fixed distance, tup×vup=tdown×vdown, so tup=tdown×vupvdown, with vdown=b+c and vup=b−c.
Let boat speed b=36k and current c=5k (ratio 36:5).
Same / Similar Concept — real previous-year questions on the same or a closely similar concept, not this exact question.
CBSE 2025Set 465/S/WXYZ/41 markMCQ
Q.A man can row 6 km/h in still water. It takes him twice as long to row up as to row down the river. Then, the speed of the stream is : (A) 2 km/h (B) 4 km/h (C) 6 km/h (D) 8 km/h
›Reveal solutionSolution
With still-water speed 6 km/h, the upstream time being twice the downstream time forces the stream speed to be 2 km/h.
Downstream speed =u+s, upstream speed =u−s, and time =speeddistance, where u = speed in still water, s = speed of stream.
Let the stream speed be s km/h; still-water speed u=6 km/h.
For a fixed distance d: time up =6−sd, time down =6+sd. …