Q.If A=[1−201] and B=[−5−1010−5], then AB is :
Concept understanding — Matrix Multiplication Properties
Matrix Multiplication: Why It Works the Way It Does
You already know how to multiply numbers. 3×5=15. Simple. Matrix multiplication looks different — and it is different — but there's a reason for every rule.
The Intuition: A Factory Analogy
Imagine you run a factory that makes two products: chairs and tables. Each product needs raw materials: wood and metal.
Let the first matrix tell you how much of each material goes into each product:
| Wood | Metal | |
|---|---|---|
| Chair | 2 | 1 |
| Table | 3 | 4 |
This is a 2×2 matrix: A=[2314].
Now suppose you have two different price lists for wood and metal — one from Supplier X, one from Supplier Y:
| Supplier X | Supplier Y | |
|---|---|---|
| Wood | 5 | 6 |
| Metal | 7 | 8 |
This is a 2×2 matrix: B=[5768].
You want to know: What is the total cost of making one chair using Supplier X's prices? You take the wood cost (2×5) plus the metal cost (1×7) = 10+7=17.
That single number — 17 — is the first entry of the product matrix AB. It comes from the first row of A (chair's material needs) dotted with the first column of B (Supplier X's prices).
Matrix multiplication is row times column. Each entry (i,j) of AB is the dot product of row i of A with column j of B.
The Precise Definition
If A is an m×n matrix and B is an n×p matrix, then their product C=AB is an m×p matrix where:
cij=∑k=1naikbkj
That sum is just a compact way of saying: multiply each element in row i of A by the corresponding element in column j of B, then add them all up.
The number of columns in A must equal the number of rows in B. If A is 3×2 and B is 2×4, you can multiply — the inner dimensions match (2 = 2). If A is 3×2 and B is 3×3, you cannot. The operation is undefined.
Properties That Hold (and One That Doesn't)
1. Associativity: (AB)C=A(BC) — as long as the dimensions line up, the grouping doesn't matter. This is a lifesaver in calculations.
2. Distributivity: A(B+C)=AB+AC and (A+B)C=AC+BC — exactly like numbers.
3. Identity: There is an identity matrix I (1's on the diagonal, 0's elsewhere) such that AI=A and IA=A.
Matrix multiplication is NOT commutative. In general, AB=BA. Even when both products are defined, they rarely give the same result. This is the single most important difference from ordinary multiplication.
Why Commutativity Fails
Go back to the factory. AB gave you the cost of each product under each supplier's prices. What would BA mean? That would be multiplying the price matrix by the material matrix — a completely different operation with a different interpretation. The dimensions might not even match.
In general, if A is m×n and B is n×m, then AB is m×m while BA is n×n. They can't be equal unless m=n, and even then they usually aren't.
A Quick Example
Let A=[1324] and B=[0110].
AB=[(1)(0)+(2)(1)(3)(0)+(4)(1)(1)(1)+(2)(0)(3)(1)+(4)(0)]=[2413]
BA=[(0)(1)+(1)(3)(1)(1)+(0)(3)(0)(2)+(1)(4)(1)(2)+(0)(4)]=[3142]
AB=BA. The order matters.
When you see AB, think: "Apply transformation B first, then transformation A." The rightmost matrix acts first on your vector. This is why AB and BA are different — you're applying the same two operations in opposite order.
The Bottom Line
Matrix multiplication is row-times-column with matching inner dimensions. It is associative and distributive but not commutative. Every property follows from this definition — and the non-commutativity is what makes matrix algebra richer (and trickier) than ordinary arithmetic.
Multiplying the lower-triangular A by B row-by-column gives AB=[−5010−25]; the key entries are the second row (−2)(−5)+1(−10)=0 and (−2)(10)+1(−5)=−25.
(d) [−5010−25]
Standard row-into-column matrix product gives AB=[−5010−25].
For 2×2 matrices, (AB)ij=∑kAikBkj — each entry is a row of A dotted with a column of B.
- A=[1−201], B=[−5−1010−5].
- (AB)11=1(−5)+0(−10)=−5; (AB)12=1(10)+0(−5)=10.
- (AB)21=(−2)(−5)+1(−10)=10−10=0; (AB)22=(−2)(10)+1(−5)=−20−5=−25.
- Thus AB=[−5010−25], matching option (d).
(d) [−5010−25]
- CBSE 2023Set 465/EF1GH/41 markMCQQ.If A=[1−201] and B=[−5−1010−5], then AB is :(a) [−5010−5](b) [025−510](c) [10−5−250](d) [−5010−25]
›Reveal solutionSolution
Standard row-into-column matrix product gives AB=[−5010−25].
For 2×2 matrices, (AB)ij=∑kAikBkj — each entry is a row of A dotted with a column of B.
- A=[1−201], B=[−5−1010−5].
- (AB)11=1(−5)+0(−10)=−5; (AB)12=1(10)+0(−5)=10.
- (AB)21=(−2)(−5)+1(−10)=10−10=0; (AB)22=(−2)(10)+1(−5)=−20−5=−25.
- Thus AB=[−5010−25], matching option (d).
✓Final answer(d) [−5010−25]
- CBSE 2023Set 465/EF1GH/41 markMCQQ.A and B are square matrices each of order 3 such that ∣A∣=−1 and ∣B∣=3. What is the value of ∣3AB∣ ?(a) −9(b) −18(c) −27(d) −81
›Reveal solutionSolution
Using ∣kA∣=kn∣A∣ and ∣AB∣=∣A∣∣B∣ with n=3: ∣3AB∣=27(−1)(3)=−81.
For square matrices of order n: ∣kA∣=kn∣A∣ and ∣AB∣=∣A∣∣B∣.
- Order n=3, so the scalar 3 pulls out as 33=27: ∣3AB∣=27∣AB∣.
- ∣AB∣=∣A∣∣B∣=(−1)(3)=−3.
- Therefore ∣3AB∣=27×(−3)=−81.
- A common error is forgetting the exponent n=3 (giving −9, option (a)); the factor is 33, not 3.
✓Final answer(d) −81
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