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Q.(a) Solve the following system of equations by Cramer's rule : 2x−y=17, 3x+5y=62x - y = 17,\ 3x + 5y = 6

(OR)
(b) Determine the integral value(s) of xx for which the matrix AA is singular : A=[x+1−34−5x+2241x−6]A = \begin{bmatrix} x+1 & -3 & 4 \\ -5 & x+2 & 2 \\ 4 & 1 & x-6 \end{bmatrix}
CBSECBSE Class XII Board 2023Subjective· 2mImportance★★★★★
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  1. x=7, y=−3x=7,\ y=-3;
  2. singular only at the integer x=0x=0.

Part (a) — Cramer's rule for 2x−y=17, 3x+5y=62x-y=17,\ 3x+5y=6

x=DxD,y=DyDx=\dfrac{D_x}{D},\quad y=\dfrac{D_y}{D}, where D=∣a1b1a2b2∣D=\begin{vmatrix}a_1&b_1\\a_2&b_2\end{vmatrix} is the coefficient determinant and Dx,DyD_x,D_y replace the respective column by the constants.

  1. D=∣2−135∣=2(5)−(−1)(3)=10+3=13.D=\begin{vmatrix}2&-1\\3&5\end{vmatrix}=2(5)-(-1)(3)=10+3=13.
  2. Dx=∣17−165∣=17(5)−(−1)(6)=85+6=91.D_x=\begin{vmatrix}17&-1\\6&5\end{vmatrix}=17(5)-(-1)(6)=85+6=91.
  3. Dy=∣21736∣=2(6)−17(3)=12−51=−39.D_y=\begin{vmatrix}2&17\\3&6\end{vmatrix}=2(6)-17(3)=12-51=-39.
  4. x=9113=7,y=−3913=−3.x=\dfrac{91}{13}=7,\qquad y=\dfrac{-39}{13}=-3.

Part (b) — integral xx making AA singular

AA is singular   ⟺  det⁡A=0\iff \det A=0, where A=[x+1−34−5x+2241x−6].A=\begin{bmatrix}x+1&-3&4\\-5&x+2&2\\4&1&x-6\end{bmatrix}.

  1. Expand along row 1: det⁡A=(x+1)[(x+2)(x−6)−2]+3[(−5)(x−6)−8]+4[−5−4(x+2)].\det A=(x+1)\big[(x+2)(x-6)-2\big]+3\big[(-5)(x-6)-8\big]+4\big[-5-4(x+2)\big]. …

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