Q.Write a user-defined function TotalPrice() in C++ to read each object of a binary file STOCK.DAT, and display the Name from all such records whose Price is above 150. Assume that the file STOCK.DAT is created with the help of objects of class Stock, which is defined below: class Stock { char Name[20]; float Price; public: char* RName() { return Name; } float RPrice() { return Price; } };

Part (a)

Open NOTES.TXT in read mode, read its entire content with read(), convert to capitals with the string method upper(), and print it. The with block closes the file automatically.

def Show_words():
    with open('NOTES.TXT', 'r') as f:
        content = f.read()
        print(content.upper())

For This is a test file:

THIS IS A TEST FILE …

Both functions use binary file input with filtering: open with ios::binary, read whole objects with read((char*)&obj, sizeof(obj)) in a while loop (the stream is false at end of file), test a condition, and output the matches.

Part (a)

The Stock class exposes RName() and RPrice(). Read each object and print the name when the price is above 150.

void TotalPrice() {
    ifstream fin("STOCK.DAT", ios::binary);
    Stock S;
    while (fin.read((char*)&S, sizeof(S))) {
        if (S.RPrice() > 150)
            cout << S.RName() << endl;
    }
    fin.close();
}
``` …

Part (a)

Read the whole file, break it into words with split(), and test each word against the set IS, TO, UP. (The check is on whole words, so UPWARD would not count as UP.)

def ISTOUPCOUNT():
    f = open("WRITER.TXT", "r")
    data = f.read()
    f.close()
    count = 0
    for word in data.split():
        if word in ("IS", "TO", "UP"):
            count += 1
    print("Count of IS TO and UP is", count)

For the sample content IT IS UP TO US TO TAKE CARE ... GOVERNMENT TO TAKE RESPONSIBILITY, the matches are IS (2), TO (3), UP (1) = 6:

Count of IS TO and UP is 6 …