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Exercises · 7.15

Q.Explain why is ortho nitrophenol more acidic than ortho methoxyphenol?

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The key difference lies in the electronic effects of the substituents: the nitro group (−NO2-\text{NO}_2) is a strong electron-withdrawing group that stabilises the phenoxide ion through both inductive and resonance effects, while the methoxy group (−OCH3-\text{OCH}_3) is an electron-donating group that destabilises the phenoxide ion, making ortho-nitrophenol more acidic.

Why This Question Matters

Acidity of phenols is a classic topic in organic chemistry because it tests your understanding of how substituents influence electron density and ion stability. The ortho position is especially interesting — unlike para or meta, it introduces steric effects and intramolecular hydrogen bonding, which can either enhance or reduce acidity. Here, we compare two ortho-substituted phenols: one with a nitro group (oo-nitrophenol) and one with a methoxy group (oo-methoxyphenol).

The core idea: the more stable the conjugate base (phenoxide ion), the stronger the acid. So we need to compare how the substituent affects the stability of the phenoxide ion.


Step-by-Step Reasoning

1. Recall the baseline: phenol itself

Phenol (C6H5OH\text{C}_6\text{H}_5\text{OH}) is weakly acidic because the phenoxide ion (C6H5O−\text{C}_6\text{H}_5\text{O}^-) is stabilised by resonance — the negative charge can be delocalised into the aromatic ring. The pKa\text{p}K_a of phenol is about 10.

Any substituent that withdraws electron density from the oxygen will stabilise the negative charge further, making the phenol more acidic. Any substituent that donates electron density will destabilise the negative charge, making it less acidic.

2. The nitro group (−NO2-\text{NO}_2) in ortho position

The nitro group is a strong electron-withdrawing group by both:

  • Inductive effect (through sigma bonds): pulls electrons away from the ring due to the high electronegativity of nitrogen and oxygen.
  • Resonance effect (through pi system): the nitro group has a positive nitrogen that can accept electron density from the ring, especially at ortho and para positions.

In oo-nitrophenol, the resonance effect is particularly powerful. When the phenoxide ion forms, the negative charge can be delocalised onto the nitro group:

Resonance stabilisation of oo-nitrophenoxide ion:

The negative charge can be delocalised onto the oxygen atoms of the nitro group, creating additional resonance structures.\text{The negative charge can be delocalised onto the oxygen atoms of the nitro group, creating additional resonance structures.}

This extra delocalisation significantly stabilises the phenoxide ion, making oo-nitrophenol a stronger acid than phenol itself (pKa≈7.2\text{p}K_a \approx 7.2).

3. The methoxy group (−OCH3-\text{OCH}_3) in ortho position

The methoxy group is an electron-donating group by:

  • Resonance effect: the lone pairs on oxygen can be donated into the ring, increasing electron density at ortho and para positions.
  • Inductive effect: slightly electron-withdrawing (due to oxygen's electronegativity), but the resonance effect dominates.

In oo-methoxyphenol, when the phenoxide ion forms, the methoxy group donates electron density into the ring. This increases the negative charge density on the oxygen, making the phenoxide ion less stable (more basic). Hence, oo-methoxyphenol is a weaker acid than phenol (pKa≈10.2\text{p}K_a \approx 10.2).

Watch out

A common mistake is to think that the methoxy group's inductive withdrawal (due to oxygen's electronegativity) makes it electron-withdrawing overall. It does not — the resonance donation is far stronger, so the net effect is electron-donating. Always check the resonance structures.

4. Direct comparison: ortho vs ortho

Now we compare the two:

| Property | oo-Nitrophenol | oo-Methoxyphenol | …

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