Q.Give the structures and IUPAC names of monohydric phenols of molecular formula, C7H8O.
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IUPAC Nomenclature (Organic Compounds)
IUPAC nomenclature is a systematic way to name a compound so that its name alone tells you its exact structure, with no ambiguity. Every organic name follows the same underlying recipe, whatever the functional group.
The Recipe
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Identify the principal characteristic group. If the molecule has a functional group senior enough to be named as a suffix (carboxylic acid > ester > amide > nitrile > aldehyde > ketone > alcohol > amine, and so on down the seniority order), that group decides the suffix and must be included in the parent chain. A halogen is never senior enough to be a suffix — it is always named as a prefix ("halo-"), whatever else is present.
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Choose the parent chain. The parent is the longest continuous carbon chain that contains the principal characteristic group (if there is one). Among chains of the same length, the one with the most substituents wins.
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Number the chain. Number from whichever end gives the LOWEST LOCANT to the principal characteristic group first. If there is no principal group (e.g. a simple haloalkane, or an alkene with a halogen substituent), lowest locant goes to the site of unsaturation (double/triple bond) first, then to substituents as a set.
Watch outWhen two numbering directions give the SAME locant for the principal group/unsaturation (a genuine tie), the tie-break is the lowest locant SET for the substituents as a group — compare the two sets at their first point of difference. Only if the sets are themselves tied does the alphabetically-first substituent get the lower number.
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Name and cite the substituents as prefixes, in alphabetical order (ignoring multiplying prefixes like di-/tri- but not ignoring structural prefixes like iso-/cyclo-), each with its own locant.
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Assemble the name: locants + substituent prefixes (alphabetical) + parent chain name + suffix (if any).
Worked Example
CH3−CH(Cl)−CH(CH3)−CH2−CH3: the longest chain is 5 carbons (pentane), no principal characteristic group (just a halogen substituent), so number for the lowest locant set. From the left: Cl at C2, methyl at C3 → set {2,3}. From the right: methyl at C3, Cl at C4 → set {3,4}. {2,3} is lower, so numbering from the left wins: 2-chloro-3-methylpentane. …
Why this formula?
IUPAC Nomenclature: Why the Rules Work the Way They Do
IUPAC nomenclature is not a single formula, but a system of rules designed to give every organic compound a unique, unambiguous name. The "why" behind these rules lies in clarity, consistency, and communication — ensuring that a chemist in Tokyo and one in Toronto draw the same structure from the same name.
1. The Core Principle: The Longest Carbon Chain
Rule: Identify the longest continuous chain of carbon atoms. This becomes the parent chain (e.g., pentane, hexane).
Why?
- The longest chain represents the backbone of the molecule.
- It gives the most stable, fundamental name — shorter chains would be branches, not the main structure.
- Example: In a molecule with 5 carbons in a row and a 2-carbon branch, calling it "pentane" (not "ethane") tells you the core skeleton is 5 carbons long.
Key idea: The parent chain is the maximum continuous path — not necessarily the one that looks "straight" on paper.
2. Numbering: Lowest Locants (The "First Point of Difference" Rule)
Rule: Number the parent chain so that substituents get the smallest possible numbers. When there's a tie, compare the first point of difference.
Why?
- This ensures reproducibility — two chemists will always number the same way.
- It avoids ambiguity: "2-methylpentane" is unambiguous; "3-methylpentane" would be a different compound.
- The first point of difference rule: If you have substituents at positions 2,4 and 3,5, choose 2,4 because 2 < 3 (the first number is smaller).
Example:
- For a methyl group on carbon 2 vs. carbon 4 of a 5-carbon chain:
- 2-methylpentane (correct)
- 4-methylpentane (wrong — higher number)
3. Alphabetical Order of Substituents
Rule: List substituents in alphabetical order (ignoring prefixes like di-, tri-, sec-, tert- but not iso-).
Why?
- Alphabetical order is a universal sorting convention — no need to remember priority based on size or complexity.
- It makes names searchable and predictable.
- Example: "3-ethyl-2-methylpentane" (e before m) — not "2-methyl-3-ethylpentane".
Exception: Prefixes like iso- and neo- are considered part of the name (e.g., isopropyl comes before methyl because "i" < "m").
4. Multiple Bonds: The "Lowest Locant" Rule for Alkenes/Alkynes
Rule: Number the chain so that the double or triple bond gets the lowest possible number, even if it means giving a substituent a higher number.
Why?
- The functional group (alkene/alkyne) is more important than alkyl substituents.
- The bond position defines the compound's reactivity and geometry.
- Example: In pent-2-ene (not pent-3-ene), the double bond is between carbons 2 and 3 — the lower number (2) is used.
Priority order:
- Principal functional group (e.g., -OH, -COOH, C=C)
- Multiple bonds
- Substituents (alkyl, halo, etc.)
5. The "Suffix" and "Prefix" System …
Concept: IUPAC Nomenclature of Monohydric Phenols
A monohydric phenol has one –OH group directly attached to a benzene ring. For C7H8O, the benzene ring (C6H5) accounts for 6 carbons and 5 hydrogens, leaving one extra carbon and three hydrogens — that extra carbon must be a methyl substituent on the ring.
Reasoning steps:
- The –OH group is the principal functional group (suffix: -ol). The benzene ring is the parent chain (phenol).
- The methyl group can be placed at three positions relative to –OH: ortho (1,2), meta (1,3), or para (1,4).
- Name each isomer using locants, with –OH at position 1 (implied in "phenol").
Structures and IUPAC names: …
The molecular formula C7H8O with a phenolic –OH group means a benzene ring plus one methyl substituent and one –OH group — that is, a methylphenol (cresol). The three positional isomers are 2-methylphenol (o-cresol), 3-methylphenol (m-cresol), and 4-methylphenol (p-cresol).
The key to solving this is to first recognise what “monohydric phenol” means. A phenol has a hydroxyl group (–OH) directly attached to a benzene ring. “Monohydric” tells us there is exactly one such –OH group. So the core is a benzene ring (C6H5–) with one –OH, which accounts for C6H5O (that’s 6 carbons, 5 hydrogens, 1 oxygen). The molecular formula given is C7H8O. Subtract the phenol core: C7H8O−C6H5O=CH3. That leftover is exactly one methyl group (−CH3). So the molecule is a benzene ring with an –OH and a –CH₃ attached — a methylphenol, commonly called a cresol.
Now, the methyl group and the hydroxyl group can be placed in three different relative positions on the benzene ring. These are the ortho, meta, and para isomers. In IUPAC nomenclature, we number the ring so that the –OH gets the lowest possible number (since –OH is the principal functional group for phenols). The methyl group then takes the position number accordingly.
Let’s go through each isomer step by step.
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Ortho isomer — The methyl group is on carbon 2, adjacent to the –OH (which is on carbon 1).
Structure: a benzene ring with –OH at position 1 and –CH₃ at position 2.
IUPAC name: 2-methylphenol. Common name: o-cresol.
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Meta isomer — The methyl group is on carbon 3, one carbon away from the –OH.
Structure: –OH at position 1, –CH₃ at position 3.
IUPAC name: 3-methylphenol. Common name: m-cresol.
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Para isomer — The methyl group is on carbon 4, directly opposite the –OH.
Structure: –OH at position 1, –CH₃ at position 4.
IUPAC name: 4-methylphenol. Common name: p-cresol. …
Method: Systematic Isomer Enumeration + IUPAC Nomenclature
This method works by first listing all possible structural isomers (different carbon skeletons and positions of the –OH group), then naming each according to IUPAC rules.
Step 1: Determine the molecular formula and identify the functional group
- Formula: C7H8O
- “Monohydric phenol” means one –OH group directly attached to a benzene ring.
- So the benzene ring contributes C6H5 — the remaining part is CH3 (a methyl group).
Thus, all isomers are methylphenols (cresols) — one methyl group and one hydroxyl group on the benzene ring.
Step 2: Enumerate positional isomers
The –OH and –CH3 groups can be placed in three relative positions on the benzene ring:
| Position of –CH3 relative to –OH | IUPAC name prefix |
|---|---|
| Adjacent (1,2) | ortho- (or 2-) |
| One carbon apart (1,3) | meta- (or 3-) |
| Opposite (1,4) | para- (or 4-) |
Step 3: Draw structures and assign IUPAC names
1. 2-Methylphenol (ortho-cresol)
OH
|
— C₆H₄ — CH₃ (at position 2)
- IUPAC: 2-methylphenol
- Common name: o-cresol
2. 3-Methylphenol (meta-cresol)
OH
|
— C₆H₄ — CH₃ (at position 3)
- IUPAC: 3-methylphenol
- Common name: m-cresol …
Step 1: Understand the molecular formula
The formula is C7H8O.
For a monohydric phenol, we have:
- A benzene ring (C6H5–)
- One –OH group (phenolic)
- Remaining: C7H8O−C6H5OH=CH3
So the extra carbon is a methyl group attached to the ring.
Step 2: The correct structures and names
There are three positional isomers:
| Structure | IUPAC Name |
|---|---|
| 2-methylphenol | 2-methylphenol (or o-cresol) |
| 3-methylphenol | 3-methylphenol (or m-cresol) |
| 4-methylphenol | 4-methylphenol (or p-cresol) |
All are monohydric phenols with formula C7H8O.
Common Mistakes & How to Avoid Them
✗ Mistake 1: Including benzyl alcohol as a monohydric phenol
Why it's wrong:
Benzyl alcohol (C6H5CH2OH) has the –OH on a side chain, not directly on the benzene ring. That makes it an alcohol, not a phenol.
How to avoid:
Remember: phenol = –OH directly attached to an aromatic ring. If the –OH is on a carbon chain attached to the ring, it's an alcohol.
✗ Mistake 2: Forgetting the methyl group can be at positions 2, 3, or 4
Why it's wrong:
Some students only write o-cresol (2-methylphenol) and p-cresol (4-methylphenol), missing the m-cresol (3-methylphenol).
How to avoid:
Always systematically check all possible positions on the ring: 2, 3, and 4 (since position 1 is taken by –OH).
✗ Mistake 3: Using common names instead of IUPAC names
Why it's wrong:
"Cresol" is a common name. In exams, IUPAC names like 2-methylphenol are required.
How to avoid:
Learn the IUPAC naming rules:
- Phenol is the parent.
- Substituents are named as prefixes with locants.
- Number the ring so that –OH gets position 1.
✗ Mistake 4: Incorrect numbering (giving –OH a number > 1)
Why it's wrong:
In phenols, the –OH group always gets position 1 by priority. Some students number from the methyl group.
How to avoid: …
Showing the 12 most recent of 97 on this concept.
- CBSE 2026Set A1 markMCQQ.The IUPAC name of CH3CH2COCH2CH3 is(a) Diethyl ketone(b) 3-Pentanone(c) 2-Pentanone(d) Methyl propyl ketone
›Reveal solutionSolution
Number the five-carbon chain to give the C=O the lowest locant: the ketone carbon is C-3, so the IUPAC name is pentan-3-one (3-pentanone).
Structure: CH3-CH2-CO-CH2-CH3. The longest chain containing the carbonyl has 5 carbons -> pentanone. Numbering from either end places the carbonyl carbon at position 3. Hence the IUPAC na …
- CBSE 2026Set ANNUAL1 markMCQQ.IUPAC name of [a benzene ring with an -OC2H5 (ethoxy) group attached] is(a) Benzyl ethoxide(b) Benzene ethoxide(c) Ethoxybenzene(d) Ethoxybenzoyl
›Reveal solutionSolution
Simple ethers with one aromatic and one alkyl group are IUPAC-named as 'alkoxy' + 'benzene', treating the -OR group as a substituent on the ring.
The compound is a benzene ring bearing an ethoxy substituent (-O-C2H5). Following IUPAC substitutive nomenclature for ethers, the smaller/simpler group's oxygen chain is named as an 'alkoxy' prefix attached to the parent (here benzene):
-OC2H5 = ethoxy group
So the compound is Ethoxybenzene (common name: phenetole).
…
- CBSE 2026Set ANNUAL1 markMCQQ.IUPAC name of CH3COOH is:(a) Ethanol(b) ethanoic acid(c) Ethanal(d) ethane
›Reveal solutionSolution
CH₃COOH is acetic acid, IUPAC name ethanoic acid.
CH₃COOH is a two-carbon carboxylic acid, commonly called acetic acid. In IUPAC nomenclature, carboxylic acids are named by replacing the "-e" of the corresponding alkane name with "-oic …
- CBSE 2026Set ANNUAL1 markMCQQ.The IUPAC name of Formic acid is :(a) Methanoic acid(b) Ethanoic acid(c) Ethandioic acid(d) Methandioic acid
›Reveal solutionSolution
Formic acid, HCOOH, is the one-carbon carboxylic acid, named methanoic acid by IUPAC rules.
Formic acid has the structure H–COOH (a single carbon bearing the carboxyl group). To name a carboxylic acid by IUPAC nomenclature:
- Select the longest carbon chain including the –COOH carbon.
- Replace the terminal '-e' of the corresponding alkane name with '-oic acid'.
Here the chain has just one carbon (methane), so the name becomes methanoic acid.
…
- CBSE 2026Set ANNUAL1 markMCQQ.The IUPAC name of isobutyl chloride is(a) 2-chlorobutane(b) 1-chloro-2-methyl propane(c) 2-chloro-2-methyl propane(d) 1-chlorobutane
›Reveal solutionSolution
Isobutyl chloride has the structure (CH3)2CH-CH2-Cl. Number the longest chain (propane, 3 carbons) so the substituent (Cl) gets the lowest locant, then name the methyl branch.
Structure of isobutyl chloride: (CH3)2CH-CH2-Cl
This can be redrawn as: Cl-CH2-CH(CH3)-CH3
Step 1: Identify the longest carbon chain containing the point of attachment of Cl. That's a 3-carbon (propane) chain: C1(CH2Cl)-C2(CH, bearing a methyl branch)-C3(CH3).
…
- CBSE 2026Set ANNUAL1 markQ.Write IUPAC name of the following compound:
›Reveal solutionSolution
Numbering the 6-carbon chain from the -COOH carbon (C1) puts the ketone at C4 and the terminal bromine at C6, giving 6-bromo-4-oxohexanoic acid.
The drawn structure is a straight 6-carbon chain: BrCH2-CH2-CO-CH2-CH2-COOH, i.e. a terminal -CH2Br at one end and -COOH at the other, with a ketone in between.
- The carboxylic acid (-COOH) is the senior group and is numbered C1.
- Numbering from that end: C1 (COOH), C2 (CH2), C3 (CH2), C4 (the ketone C=O), C5 (CH2), C6 (the terminal CH2Br). …
- CBSE 2026Set ANNUAL1 markMCQQ.The IUPAC name of CH3COOH is(a) Acetic acid(b) Formic acid(c) Ethanoic acid(d) Methanoic acid
›Reveal solutionSolution
CH3COOH = ethanoic acid (IUPAC).
CH3COOH has two carbon atoms and a −COOH group. In IUPAC nomenclature, a two-carbon carboxylic acid is 'ethan' (two carbons) + 'oic acid' = ethanoic acid. Its common (trivial) …
- CBSE 2026Set ANNUAL1 markMCQQ.The IUPAC name of CH3−CH(OH)−CH3 is(a) Propan-1-ol(b) Propan-2-ol(c) n-propyl alcohol(d) Isopropyl alcohol
›Reveal solutionSolution
CH3−CH(OH)−CH3 = propan-2-ol.
The chain has three carbons (propane). The −OH group is attached to the central (second) carbon. Numbering to give the OH the lowest locant places it at position 2, so the …
- CBSE 2026Set ANNUAL1 markMCQQ.The structure of a valuable organic compound used as solvent in many chemical industries is shown below (a central carbon bearing a CH₃ group above, a CH₃ group to the left, an OH group below, and a –CH₂–OCH₃ group to the right). The IUPAC name of the organic compound is(a) 1-methoxy-2-methylpropan-2-ol(b) 3-methoxy-2-methylpropan-2-ol(c) 1-methoxy-3-methylpropan-3-ol(d) 2-methoxy-2-methylpropan-2-ol
›Reveal solutionSolution
The structure is (CH₃)₂C(OH)CH₂OCH₃; the parent is propan-2-ol with a 2-methyl and a 1-methoxy substituent, giving 1-methoxy-2-methylpropan-2-ol — option (A).
The central carbon bears two CH3 groups, an OH, and a −CH2−OCH3 group, so the molecule is
(CH3)2C(OH)−CH2−OCH3.
Naming:
- The longest carbon chain containing the –OH is three carbons (propane): C1=CH2(OCH3), C2=C(OH)(CH3), C3=CH3. …
- CBSE 2025Set 56/5/11 markMCQQ.The IUPAC name for CH3−CH2−N(CH3)−CH2−CH2−CH3 is : (A) N-methylpentan-2-amine (B) N-ethyl-N-methylpropan-1-amine (C) N,N-diethylpropan-1-amine (D) N,N-dimethylpropan-1-amine
›Reveal solutionSolution
The compound is a secondary amine with an ethyl and a methyl group on the nitrogen, and a three-carbon chain as the parent. The correct IUPAC name is N-ethyl-N-methylpropan-1-amine, which corresponds to option (B).
The key to naming amines under IUPAC rules is to identify the longest continuous carbon chain attached to the nitrogen — that becomes the parent alkane name, with the suffix "-amine". The other groups on the nitrogen are treated as substituents, prefixed with "N-" to show they are attached to the nitrogen atom, not to the carbon chain.
Let's break this down step by step.
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Draw the structure from the given condensed formula.
The formula is CH3−CH2−N(CH3)−CH2−CH2−CH3.
The nitrogen has three bonds: one to an ethyl group (−CH2CH3), one to a methyl group (−CH3), and one to a propyl group (−CH2CH2CH3). So the molecule is:
CH3 | CH3-CH2-N-CH2-CH2-CH3The nitrogen is connected to three different alkyl groups: ethyl, methyl, and propyl.
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Identify the parent chain.
The IUPAC rule for amines: the parent chain is the longest continuous carbon chain attached directly to the nitrogen. Here, the chain on the right is CH2−CH2−CH3 — that's three carbons, a propyl group. The chain on the left is CH2−CH3 — two carbons, an ethyl group. The methyl group (CH3) is just one carbon.
So the longest chain is the three-carbon chain (propyl). The parent name becomes propan-1-amine (since the nitrogen is at the end of the chain, carbon 1).
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Name the substituents on the nitrogen.
The other two groups attached to the nitrogen are an ethyl group (−CH2CH3) and a methyl group (−CH3). Since they are on the nitrogen, not on the carbon chain, they are prefixed with "N-".
Alphabetically, ethyl comes before methyl. So we write N-ethyl-N-methyl.
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Combine the parts.
The full name is: N-ethyl-N-methylpropan-1-amine. …
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- CBSE 2025Set X11 markMCQQ.The IUPAC name of H3C−Br∣CH−CH2−∣∣OC−H(a) 3–bromobutyraldehyde(b) 2–bromopropanaldehyde(c) 3–bromobutanal(d) 2–bromobutanal
›Reveal solutionSolution
The compound is CH3-CH(Br)-CH2-CHO, a 4-carbon aldehyde with bromine on C-3 → 3-bromobutanal.
The structure is H3C-CH(Br)-CH2-CHO.
- The principal functional group is the aldehyde (–CHO), so it gets the lowest locant. Numbering starts at the carbonyl carbon: C1 = CHO, C2 = CH2, C3 = CH(Br), C4 = CH3.
- Longest chain = 4 carbons → butanal. …
- CBSE 2025Set D1 markMCQQ.The IUPAC name of CH3COOC2H5 is(a) Methyl propanoate(b) Ethyl ethanoate(c) Acetoethane(d) Ethoxyethane
›Reveal solutionSolution
CH3COOC2H5 = ethyl ethanoate (common name ethyl acetate).
The compound is an ester derived from ethanoic acid (CH3COOH) and ethanol (C2H5OH). An ester R-COO-R' is named as 'alkyl alkanoate':
- The alkyl group from the alcohol part (C2H5) -> ethyl …
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