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Q.Derive the formula for refraction of light through any spherical surface (μ - 1)/R = μ/v − 1/u, where symbols have their usual meaning. OR Find the expression for the magnifying power by drawing the ray diagram of compound microscope —

(i) when the final image is formed at least distance of distinct vision;
(ii) when the final image is formed at infinity.
Chhattisgarh CgbseCGBSE Intermediate Board 2022Subjective· 5mImportance★★★★★
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Applying Snell's law to a paraxial ray refracting at a spherical surface, and expressing the small angles involved in terms of the object distance u, image distance v and radius of curvature R, leads directly to μ/v − 1/u = (μ−1)/R.

Setup: Consider a spherical surface of radius of curvature R, with pole P, separating a rarer medium of refractive index n₁ (where a point object O lies on the principal axis) from a denser medium of refractive index n₂ (where the real image I is formed). A paraxial ray from O travelling very close to the axis strikes the surface at a point M (at a small height h above the axis) and refracts to meet the axis at I. A second ray travels straight along the axis without bending.

Let C be the centre of curvature of the surface. Define the (small) angles:

∠MOP=α≈h−u,∠MCP=β≈hR,∠MIP=γ≈hv\angle MOP = \alpha \approx \frac{h}{-u}, \qquad \angle MCP = \beta \approx \frac{h}{R}, \qquad \angle MIP = \gamma \approx \frac{h}{v}

using the Cartesian sign convention (distances measured from P, positive in the direction of the incident light; object distance is therefore written −u with u itself the signed value).

Using the exterior-angle property of a triangle:

In triangle OMC, the angle of incidence i (angle between the incident ray and the normal MC) is the exterior angle at M:

i=α+βi = \alpha + \beta

In triangle MIC, β is the exterior angle at C, equal to the sum of the two opposite interior angles r (angle of refraction) and γ:

β=r+γ⇒r=β−γ\beta = r + \gamma \quad\Rightarrow\quad r = \beta - \gamma

Applying Snell's law for the small (paraxial) angles, n1sin⁡i=n2sin⁡r≈n1i=n2rn_1\sin i = n_2\sin r \approx n_1 i = n_2 r:

n1(α+β)=n2(β−γ)n_1(\alpha+\beta) = n_2(\beta-\gamma)

Substituting the expressions for α, β, γ (and cancelling the common factor h): …

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