Worked Examples · Example 2
Q.A wheat farmer sells in a perfectly competitive market where the price is fixed at ₹5 per kg. Prepare the TR, AR and MR schedule for sales of 1 to 5 kg, and state what it shows about the relationship between AR and MR under perfect competition.
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Step 1 — Total Revenue at a constant price of ₹5.
| Q (kg) | P (₹) | TR = P×Q (₹) | AR = TR/Q (₹) | MR = ΔTR (₹) |
|---|---|---|---|---|
| 1 | 5 | 5 | 5 | 5 |
| 2 | 5 | 10 | 5 | 5 |
| 3 | 5 | 15 | 5 | 5 |
| 4 | 5 | 20 | 5 | 5 |
| 5 | 5 | 25 | 5 | 5 |
Step 2 — Average Revenue. at every output, equal to the price.
Step 3 — Marginal Revenue. Each extra kg adds ₹5: throughout.
Step 4 — Interpretation. Because the competitive firm cannot influence price and sells all it wishes at ₹5, price does not fall as it sells more. Hence
and the AR and MR curves are the same horizontal straight line at the ruling market price. This is the defining revenue feature of perfect competition, in contrast with the falling AR and lower MR of Worked Example 1.
✓Final answer
TR (₹): 5, 10, 15, 20, 25; AR = MR = ₹5 at all outputs. Under perfect competition AR = MR = price, a single horizontal line.
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