Q.(j) The derivative of $\sqrt{x}$ with respect to $x$, is

Apply the power rule term by term: the derivative is $20x^3-9x^2+4x-11$.

Using $\dfrac{d}{dx}(x^n)=nx^{n-1}$ on $5x^4-3x^3+2x^2-11x+7$:

$\frac{d}{dx}(5x^4)=20x^3,\quad \frac{d}{dx}(-3x^3)=-9x^2,$ …

Product rule: $\dfrac{d}{dx}(uv)=u\,v'+v\,u'$.

If $u=u(x)$ and $v=v(x)$ are two differentiable functions, the derivative of their product is

$\frac{d}{dx}(uv)=u\frac{dv}{dx}+v\frac{du}{dx}.$ …

Using the power rule, $\dfrac{d}{dx}(5x^6)=30x^5$.

Step 1 — the power rule states $\dfrac{d}{dx}(x^n)=nx^{n-1}$.

Step 2 — constants multiply through (constant-multiple rule):

…

The derivative is $6r + 4$.

Using the power rule $\dfrac{d}{dr}(r^n) = n r^{n-1}$ and the fact that the derivative of a constant is $0$, differentiate each term: …

Correct option: (d) $\dfrac{1}{2\sqrt{x}}$.

Express the root as a power and use $\dfrac{d}{dx}x^n = n x^{n-1}$: …