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Question 17 of 24

Q.(d) If y=(2x3−1)4y = (2x^3 - 1)^4, find dydx\dfrac{dy}{dx}.

ChseodishaCHSE Odisha Plus Two (Class 12) Commerce Board 2019Subjective· 3mImportance★★★★★est
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dydx=24x2(2x3−1)3\dfrac{dy}{dx} = 24x^2(2x^3 - 1)^3.

Given y=(2x3−1)4y = (2x^3 - 1)^4, apply the chain rule dydx=nun−1dudx\dfrac{dy}{dx} = n u^{n-1}\dfrac{du}{dx} with u=2x3−1u = 2x^3 - 1 and n=4n = 4.

dudx=ddx(2x3−1)=6x2.\frac{du}{dx} = \frac{d}{dx}(2x^3 - 1) = 6x^2.

Therefore …

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