Skip to content
Question 24 of 24

Q.Differentiate 1+x1−x\sqrt{\frac{1+x}{1-x}} with respect to x.

ChseodishaCHSE Odisha Plus Two (Class 12) Commerce Board 2024Subjective· 3mImportance★★★★★est
100% · 24/24 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Take logs, differentiate, simplify: dydx=11+x (1−x)3/2\dfrac{dy}{dx}=\dfrac{1}{\sqrt{1+x}\,(1-x)^{3/2}}.

Let y=1+x1−x=(1+x1−x)1/2y=\sqrt{\dfrac{1+x}{1-x}}=\left(\dfrac{1+x}{1-x}\right)^{1/2}.

Take logarithms:

ln⁡y=12[ln⁡(1+x)−ln⁡(1−x)].\ln y=\tfrac12\big[\ln(1+x)-\ln(1-x)\big].

Differentiate both sides:

1ydydx=12[11+x−−11−x]=12[11+x+11−x].\frac{1}{y}\frac{dy}{dx}=\frac12\left[\frac{1}{1+x}-\frac{-1}{1-x}\right]=\frac12\left[\frac{1}{1+x}+\frac{1}{1-x}\right].

Combine the fractions:

=12⋅(1−x)+(1+x)(1+x)(1−x)=12⋅21−x2=11−x2.=\frac12\cdot\frac{(1-x)+(1+x)}{(1+x)(1-x)}=\frac12\cdot\frac{2}{1-x^2}=\frac{1}{1-x^2}.

So: …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.