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Illustrations · Q8

Q.A factory has two production departments, A and B, and one service department S. The following overheads are to be distributed among them:

(i) Rent ₹3,000 — floor area A 1,500 sq ft, B 1,000 sq ft, S 500 sq ft.
(ii) Depreciation of machinery ₹2,000 — value of machinery A ₹50,000, B ₹40,000, S ₹10,000.
(iii) Supervision ₹1,200 — number of workers A 30, B 20, S 10.
Prepare the primary distribution summary showing the overhead of each department.
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Each item is apportioned on the basis appropriate to it.

Step 1 — Rent ₹3,000 on floor area (1,500 : 1,000 : 500 = 3 : 2 : 1, total 6 parts).

  • A = 3,000 × 3/6 = ₹1,500
  • B = 3,000 × 2/6 = ₹1,000
  • S = 3,000 × 1/6 = ₹500

Step 2 — Depreciation ₹2,000 on machinery value (50,000 : 40,000 : 10,000 = 5 : 4 : 1, total 10 parts).

  • A = 2,000 × 5/10 = ₹1,000
  • B = 2,000 × 4/10 = ₹800
  • S = 2,000 × 1/10 = ₹200

Step 3 — Supervision ₹1,200 on number of workers (30 : 20 : 10 = 3 : 2 : 1, total 6 parts).

  • A = 1,200 × 3/6 = ₹600
  • B = 1,200 × 2/6 = ₹400
  • S = 1,200 × 1/6 = ₹200

Primary distribution summary:

Item (basis)Total (₹)Dept A (₹)Dept B (₹)Dept S (₹)
Rent (floor area 3:2:1)3,0001,5001,000500
Depreciation (machine value 5:4:1)2,0001,000800200
Supervision (workers 3:2:1)1,200600400200
Total6,2003,1002,200900

Wait — re-add each department column carefully: A = 1,500 + 1,000 + 600 = ₹3,100; B = 1,000 + 800 + 400 = ₹2,200; S = 500 + 200 + 200 = ₹900. Cross-check: 3,100 + 2,200 + 900 = ₹6,200, which equals the total of all items (3,000 + 2,000 + 1,200 = 6,200). The distribution therefore balances.

✓Final answer

Primary distribution totals — Department A ₹3,100, Department B ₹2,200, Service Department S ₹900; grand total ₹6,200, which agrees with the total of all overhead items apportioned.

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