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Worked Examples · Example 4
Q.

Compute the Quartile Deviation and the Coefficient of Quartile Deviation for the following distribution of marks of 50 students:

Marks0–1010–2020–3030–4040–50
No. of students51018125
Gujarat GsebTextbookSubjectiveImportance★★★★★est
50% · 6/12 Questions
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Step 1 — Build the cumulative frequency (c.f.) column.

MarksFrequency (ff)c.f.
0–1055
10–201015
20–301833
30–401245
40–50550

Total N=50N=50.

Step 2 — Locate the Q1Q_1 class. N4=12.5\dfrac{N}{4}=12.5. The c.f. first exceeding 12.5 is 15, in the class 10–20, so L=10L=10, cf=5cf=5 (c.f. before this class), f=10f=10, h=10h=10.

Q1=L+N4−cff×h=10+12.5−510×10=10+7.5=17.5Q_1 = L+\dfrac{\frac{N}{4}-cf}{f}\times h = 10+\dfrac{12.5-5}{10}\times 10 = 10+7.5 = 17.5

Step 3 — Locate the Q3Q_3 class. 3N4=37.5\dfrac{3N}{4}=37.5. The c.f. first exceeding 37.5 is 45, in the class 30–40, so L=30L=30, cf=33cf=33, f=12f=12, h=10h=10.

Q3=L+3N4−cff×h=30+37.5−3312×10=30+3.75=33.75Q_3 = L+\dfrac{\frac{3N}{4}-cf}{f}\times h = 30+\dfrac{37.5-33}{12}\times 10 = 30+3.75 = 33.75

Step 4 — Compute Q.D. and its Coefficient.

Q.D.=33.75−17.52=16.252=8.125\text{Q.D.} = \dfrac{33.75-17.5}{2} = \dfrac{16.25}{2} = 8.125 …

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