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Worked Examples · Example 2

Q.Find the quartile deviation and its coefficient for the data: 12,15,18,20,22,25,28,30,3512, 15, 18, 20, 22, 25, 28, 30, 35.

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The data is already in ascending order and n=9n = 9.

Position of Q1Q_1: n+14=9+14=2.5\dfrac{n+1}{4} = \dfrac{9+1}{4} = 2.5th value. This lies halfway between the 22nd value (1515) and the 33rd value (1818):

Q1=15+0.5 (18−15)=15+1.5=16.5.Q_1 = 15 + 0.5\,(18 - 15) = 15 + 1.5 = 16.5.

Position of Q3Q_3: 3(n+1)4=3×104=7.5\dfrac{3(n+1)}{4} = \dfrac{3 \times 10}{4} = 7.5th value. This lies halfway between the 77th value (2828) and the 88th value (3030):

Q3=28+0.5 (30−28)=28+1=29.Q_3 = 28 + 0.5\,(30 - 28) = 28 + 1 = 29.

Quartile deviation:

Q.D.=Q3−Q12=29−16.52=12.52=6.25.\text{Q.D.} = \frac{Q_3 - Q_1}{2} = \frac{29 - 16.5}{2} = \frac{12.5}{2} = 6.25.

Coefficient of Q.D.:

Q3−Q1Q3+Q1=29−16.529+16.5=12.545.5≈0.275.\frac{Q_3 - Q_1}{Q_3 + Q_1} = \frac{29 - 16.5}{29 + 16.5} = \frac{12.5}{45.5} \approx 0.275.

Independent check: the middle 50%50\% of the values lies between 16.516.5 and 2929, a spread of 12.512.5; half of that is 6.256.25, matching the Q.D. And 12.5÷45.5=0.2747…≈0.27512.5 \div 45.5 = 0.2747\ldots \approx 0.275.

✓Final answer

Q.D. =6.25= 6.25; Coefficient of Q.D. ≈0.275\approx 0.275

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