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Q.If the demand function of pizza is p=150−4xp = 150 - 4x then find the marginal revenue when demand is of 3 pizzas.

Gujarat GsebGujarat Board (GSEB) HSC Commerce Board 2026Subjective· 3mImportance★★★★★
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R=px=150x−4x2R=px=150x-4x^2; MR=dRdx=150−8xMR=\tfrac{dR}{dx}=150-8x; at x=3x=3, MR=126MR=126.

Given the demand (price) function p=150−4xp=150-4x, the total revenue is

R=p⋅x=(150−4x)x=150x−4x2.R=p\cdot x=(150-4x)x=150x-4x^2.

Marginal revenue is the derivative of total revenue with respect to xx: …

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