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Question 42 of 43

Q.Find the value of lim⁡h→0f(x+h)−f(x)h\lim_{h \to 0} \dfrac{f(x+h) - f(x)}{h} where f(x)=x, x>0f(x) = \sqrt{x},\ x > 0.

Gujarat GsebGujarat Board (GSEB) HSC Commerce Board 2026Subjective· 4mImportance★★★★★
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Rationalise: x+h−xh=1x+h+x→12x\dfrac{\sqrt{x+h}-\sqrt{x}}{h}=\dfrac{1}{\sqrt{x+h}+\sqrt{x}}\to\dfrac{1}{2\sqrt{x}}.

With f(x)=xf(x)=\sqrt{x}, the difference quotient is x+h−xh\dfrac{\sqrt{x+h}-\sqrt{x}}{h}, which is 00\tfrac00 as h→0h\to0. Multiply numerator and denominator by the conjugate (x+h+x)(\sqrt{x+h}+\sqrt{x}): …

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