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Worked Examples · Example 1

Q.Differentiate f(x)=x3f(x) = x^3 from first principles.

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✓ Free question

Given: f(x)=x3f(x) = x^3; differentiate from first principles.

Step 1 — Write the limit definition: f′(x)=lim⁡Δx→0f(x+Δx)−f(x)Δx=lim⁡Δx→0(x+Δx)3−x3Δxf'(x) = \lim_{\Delta x \to 0} \dfrac{f(x+\Delta x) - f(x)}{\Delta x} = \lim_{\Delta x \to 0} \dfrac{(x+\Delta x)^3 - x^3}{\Delta x}.

Step 2 — Expand (x+Δx)3(x+\Delta x)^3: (x+Δx)3=x3+3x2Δx+3x(Δx)2+(Δx)3(x+\Delta x)^3 = x^3 + 3x^2\Delta x + 3x(\Delta x)^2 + (\Delta x)^3.

Step 3 — Subtract x3x^3: numerator becomes 3x2Δx+3x(Δx)2+(Δx)33x^2\Delta x + 3x(\Delta x)^2 + (\Delta x)^3.

Step 4 — Divide by Δx\Delta x: 3x2Δx+3x(Δx)2+(Δx)3Δx=3x2+3xΔx+(Δx)2\dfrac{3x^2\Delta x + 3x(\Delta x)^2 + (\Delta x)^3}{\Delta x} = 3x^2 + 3x\Delta x + (\Delta x)^2.

Step 5 — Let Δx→0\Delta x \to 0: every remaining term containing Δx\Delta x vanishes, leaving f′(x)=3x2f'(x) = 3x^2.

Check (independent method — power rule): applying the power rule directly, ddx(x3)=3x3−1=3x2\dfrac{d}{dx}(x^3) = 3x^{3-1} = 3x^2 — matches the first-principles result exactly.

✓Final answer

f′(x)=3x2f'(x) = 3x^2

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