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Worked Examples · Example 6

Q.Differentiate y=3e2x−4ln⁡xy = 3e^{2x} - 4\ln x with respect to xx.

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Given: y=3e2x−4ln⁡xy = 3e^{2x} - 4\ln x.

Step 1 — Differentiate 3e2x3e^{2x}: using ddx(eg(x))=eg(x)g′(x)\dfrac{d}{dx}(e^{g(x)})=e^{g(x)}g'(x) with g(x)=2xg(x)=2x, g′(x)=2g'(x)=2: ddx(e2x)=2e2x\dfrac{d}{dx}(e^{2x}) = 2e^{2x}, so ddx(3e2x)=6e2x\dfrac{d}{dx}(3e^{2x}) = 6e^{2x}.

Step 2 — Differentiate −4ln⁡x-4\ln x: using ddx(ln⁡x)=1x\dfrac{d}{dx}(\ln x) = \dfrac1x: ddx(−4ln⁡x)=−4x\dfrac{d}{dx}(-4\ln x) = -\dfrac4x.

Step 3 — Combine: dydx=6e2x−4x\dfrac{dy}{dx} = 6e^{2x} - \dfrac4x. …

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