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Exercises · Q12

Q.If XX is a random variable such that Y=2X+3Y = 2X + 3, and E(X)=4E(X) = 4, Var(X)=5Var(X) = 5, find E(Y)E(Y) and Var(Y)Var(Y).

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Step 1 — Apply the linearity property of expectation. For Y=aX+bY=aX+b with a=2a=2, b=3b=3:

E(Y)=aE(X)+b=2(4)+3=8+3=11E(Y) = aE(X)+b = 2(4)+3 = 8+3 = 11

Step 2 — Apply the scaling property of variance. Adding a constant (b=3b=3) does not change the spread, and scaling by a=2a=2 scales the variance by a2a^2:

Var(Y)=a2 Var(X)=22×5=4×5=20Var(Y) = a^2\,Var(X) = 2^2 \times 5 = 4\times5 = 20 …

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