Q.Same as in Problem 4 except that the coil A is made to rotate about a vertical axis. No current flows in B if A is at rest. The current in coil A, when the current in B (at t=0) is counterclockwise and the coil A is as shown at this instant, t=0, is
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🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — Mutual Inductance
Mutual Inductance: From Intuition to Definition
Imagine you have two separate coils of wire placed near each other. You connect one coil to a battery — current starts flowing through it. Now, something strange happens in the other coil, which isn't connected to anything: a voltage appears across its ends. That voltage can even light a small bulb for an instant.
This is mutual inductance in action. One circuit "feels" the changing current in another circuit, even though they are not physically connected.
The Core Intuition
The key idea is changing magnetic fields. When current flows through a coil, it creates a magnetic field around it. If that current changes (increases or decreases), the magnetic field also changes. This changing field reaches the second coil. And a changing magnetic field, by Faraday's law, induces an electromotive force (emf) in any nearby conductor.
So mutual inductance is simply: how effectively a change in current in one coil induces a voltage in another coil.
Mutual inductance only works when the current is changing. A steady DC current produces a steady magnetic field, which induces nothing in the second coil. That's why the bulb lights only for an instant when you first connect the battery — the current is rising from zero.
The Precise Definition
Let's formalise this. Consider two coils: coil 1 and coil 2. Let I1 be the current in coil 1. This current produces a magnetic flux Φ21 through coil 2 (the flux from coil 1 that passes through coil 2).
The mutual inductance M (also written M21) is defined as the constant of proportionality between the current I1 and the flux it produces in coil 2:
Φ21=MI1
Similarly, if current I2 flows in coil 2, it produces a flux Φ12 through coil 1:
Φ12=MI2
The mutual inductance M is the same for both directions. M21=M12=M. This is a fundamental symmetry property.
Now, by Faraday's law, the induced emf in coil 2 due to a changing current in coil 1 is:
E2=−dtdΦ21=−MdtdI1
And the induced emf in coil 1 due to a changing current in coil 2 is:
E1=−MdtdI2
The negative sign is Lenz's law — the induced emf opposes the change that produced it.
Units
The SI unit of mutual inductance is the henry (H), named after Joseph Henry. From the definition:
1H=1AV⋅s=1AWb
One henry means that a current change of 1 ampere per second induces an emf of 1 volt in the other coil.
What Determines Mutual Inductance?
M depends on:
- Geometry: size, shape, number of turns of both coils
- Relative position: how close they are and how they are oriented
- Core material: if a magnetic material (like iron) is present, M increases dramatically
For two coaxial solenoids of length l, with N1 and N2 turns, and cross-sectional area A, the mutual inductance is: …
Why this formula?
Mutual Inductance: Why the Formula Holds
Mutual inductance is a beautiful example of Faraday's Law in action — it describes how a changing current in one coil can induce an EMF in a nearby coil, without any direct electrical connection.
1. The Core Idea: Flux Linkage
Imagine two coils, Coil 1 and Coil 2, placed close together.
- When a current I1 flows in Coil 1, it creates a magnetic field B1.
- Some of the magnetic field lines from Coil 1 pass through Coil 2.
- The total magnetic flux through Coil 2 due to I1 is called the mutual flux:
Φ21=flux through Coil 2 due to current in Coil 1
Key insight: For a fixed geometry (coils not moving), the mutual flux is directly proportional to the current I1:
Φ21∝I1
Why? Because B1 itself is proportional to I1 (Biot–Savart law), and the area of Coil 2 is fixed. So:
Φ21=M21I1
where M21 is the mutual inductance (a constant depending on coil shapes, sizes, turns, and relative positions).
2. Why the EMF Formula Arises
Now, if I1 changes with time, then Φ21 changes with time. By Faraday's Law, a changing flux induces an EMF in Coil 2:
E2=−dtdΦ21
Substitute Φ21=M21I1:
E2=−M21dtdI1
That's the key formula. The negative sign (Lenz's law) tells us the induced EMF opposes the change in flux.
3. Symmetry: M12=M21
If we reverse the situation — current I2 in Coil 2 induces flux Φ12 in Coil 1 — we get:
Φ12=M12I2
and
E1=−M12dtdI2
A deep result from energy conservation (or from the reciprocity theorem in electromagnetism) shows:
M12=M21=M
So we simply call it M, the mutual inductance between the two coils.
4. The Complete Formula Set
| Quantity | Expression | Why? |
|---|---|---|
| Mutual flux (Coil 2 due to Coil 1) | Φ21=MI1 | Proportionality from Biot–Savart |
| Induced EMF in Coil 2 | E2=−MdtdI1 | Faraday's Law |
| Mutual flux (Coil 1 due to Coil 2) | Φ12=MI2 | Symmetry |
| Induced EMF in Coil 1 | E1=−MdtdI2 | Faraday's Law |
5. Physical Intuition (Exam-Ready) …
Key clue: "No current flows in B when A is at rest."
- If the current in A were changing with time, then even with A held still it would change the flux through B and drive a current in B (mutual induction). The fact that a stationary A produces no current in B forces
dtdIA=0,
so A carries a constant (steady) current. …
"No current in B while A is at rest" can only hold if A's current does not change in time, so coil A carries a constant current; the given counterclockwise sense in B fixes that steady current in A as clockwise.
Reading the crucial condition
We are told: if A is at rest, no current flows in B. Suppose instead the current IA in coil A varied with time. Then, even with A held fixed, the flux it sends through B would change, and by Faraday–Lenz a current would appear in B:
εB=−MdtdIA.
Since the problem states there is no current in B for a stationary A, we must have
dtdIA=0⇒IA=constant.
So coil A is driven by a source that maintains a steady current; the only way to get a current in B is to rotate A (which changes the orientation, hence the flux through B).
Fixing the direction …
Method: Using a "No Current When Stationary" Clue to Fix Both the Nature AND Direction of a Source Current
This method is for questions that give you a negative observation ("no current flows under condition X") as the key piece of evidence, rather than a positive reading.
Steps
Step 1: Translate the stated observation into a mathematical condition
"No current flows in B when A is at rest" means the induced emf in B is exactly zero throughout that interval:
εB=−MdtdIA=0whenever A is at rest
Since this holds for the entire stationary interval — not just momentarily — you can conclude dIA/dt=0 identically: IA is a genuine constant, not merely quiet for an instant.
Step 2: Identify what DOES change to produce current in B
If IA is constant, the only way flux through B can vary is through the mutual inductance M itself changing — which happens when the rotation of A alters its orientation/effective coupling to B. This confirms the current in B only appears because A is rotating, not because A's own current is varying.
Step 3: Use the given snapshot to fix A's current direction …
- GUJCET 2026Set x1 markMCQQ.Two concentric circular coils, one of small radius r1 and the other of large radius r2, such that r1≪r2, are placed co-axially with centres coinciding. The mutual inductance M of the arrangement is proportional to ______. (A) r2r1 (B) r1r2 (C) r2r12 (D) r1r22
›Reveal solutionSolution
M=2r2μ0πr12∝r2r12.
The large coil (radius r2) produces a nearly uniform field B=2r2μ0I over the small coil. Flux through the small coil (area πr12): …
- GUJCET 2026Set x1 markMCQQ.A coil has N turns and current passes through it is I ampere then we obtain L of self inductance. Now if current is made doubled then new self inductance be ______ H. (A) L/2 (B) 2L (C) L (D) 4L
›Reveal solutionSolution
L is geometry-dependent only → unchanged when current doubles.
Self-inductance is a property of the coil's geometry (L=μ0n2Al for a solenoid), independent of the current flowing. Doubli …
- GUJCET 2025Set 031 markMCQQ.A pair of adjacent coils has a mutual inductance of 2H. If the current in one coil changes from 0 to 30A in 0.15s, what is the change of flux linkage with the other coil? (A) 300 Wb (B) 6 Wb (C) 60 Wb (D) 15 Wb
›Reveal solutionSolution
Flux linkage with the second coil is Nϕ=MI, so Δ(Nϕ)=MΔI. …
- GUJCET 2024Set 131 markMCQQ.A coil has N turns and current passes through it is I ampere then we obtain L Henry of self inductance. Now if current charge to 5I then new self inductance will be ________ H. (A) L (B) 1/5 L (C) 25 L (D) 5 L
›Reveal solutionSolution
L is a geometric constant of the coil; changing the current does not change L.
Concept. Self-inductance L=lμN2A depends on the number of turns, area, length and core — not on the current f …
- GUJCET 2022Set 171 markMCQQ.An air-cored solenoid with length 30 cm, area of cross-section 25 cm2 and number of turns 500, carries a current of 2.5 A. The current is suddenly switched off in a brief time of 10−3 s. How much is the average back emf induced across the ends of the open switch in the circuit? Ignore the variation in magnetic field near the ends of the solenoid. (A) 6.54 V (B) 65.4 V (C) 654 V (D) 0.654 V
›Reveal solutionSolution
Compute L of the solenoid, then ε=LdtdI.
Concept: Self-inductance of a solenoid L=lμ0N2A, and back emf ε=LdtdI.
L=0.30(4π×10−7)(500)2(25×10−4)=2.62×10−3 H …
- GUJCET 2022Set 171 markMCQQ.For an ideal transformer, if Ns>Np then ________. (A) Vs<Vp (B) Vs>Vp (C) Vs=Vp (D) None of these
›Reveal solutionSolution
Ideal transformer: VpVs=NpNs, so Ns>Np⇒Vs>Vp.
Concept: For an ideal transformer the voltage ratio equals the turns ratio:
VpVs=NpNs …
- GUJCET 2022Set 171 markMCQQ.A pair of adjacent coils has a mutual inductance of 1.5 H. If the current in one coil changes from 0 to 10 A in 0.5 s, what is the change of flux linkage with the other coil? (A) 30 Wb (B) 1.5 Wb (C) 15 Wb (D) 0.15 Wb
›Reveal solutionSolution
Flux linkage change =MΔI.
Concept. Mutual inductance links the flux in coil 2 to current in coil 1: N2Φ2=MI1.
Steps. …
- GUJCET 2021Set 151 markMCQQ.The self inductance L of a solenoid of length l and area of cross-section A increase ___. (Here, with fixed number of turns N). (A) l and A increase (B) l increases and A decreases (C) l decreases and A increases (D) Both l and A decrease
›Reveal solutionSolution
L∝lA at fixed N. …
- GUJCET 2021Set 151 markMCQQ.A pair of adjacent coils has a mutual inductance of 1.5 H. If the current in one coil changes from 0 to 20 A in 0.5 sec. what is the change of flux linkage with the other coil? (A) 15 Wb (B) 45 Wb (C) 30 Wb (D) 60 Wb
›Reveal solutionSolution
Flux linkage change with the second coil is ΔΦ=MΔI=1.5×20=30 Wb.
Concept: Mutual flux linkage Φ=MI, so the change is …
- GUJCET 2020Set 071 markMCQQ.What is correct for real transformer? (A) Pi>Po (B) Pi<Po (C) Pi=Po (D) All are correct
›Reveal solutionSolution
Efficiency <100% means Pi>Po.
Concept: An ideal transformer conserves power (Pi=Po), but a real transformer has copper, iron (hysteresis/eddy-current) and flux-leakage losses, so some input power is dissip …
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