Skip to content
Question of 77

Q.State and explain principle of conservation of linear momentum with the help of an example.

Jammu Kashmir JkboseJammu and Kashmir Board of School Education (Class 11) 2024Subjective· 5mImportance★★★★★
0% · 0/77 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

The principle of conservation of linear momentum follows from Newton's second and third laws: in the absence of a net external force, the total momentum of a system of interacting bodies remains constant, as illustrated by gun recoil.

Statement: In the absence of any external force acting on a system of particles, the total linear momentum of the system remains constant (conserved), both in magnitude and direction.

Derivation from Newton's laws: Consider two bodies A and B of masses m1m_1 and m2m_2 interacting with each other (e.g. during a collision), with no external force on the system. Let F⃗AB\vec{F}_{AB} be the force exerted by A on B, and F⃗BA\vec F_{BA} the force exerted by B on A.

By Newton's second law, force is the rate of change of momentum:

F⃗AB=dp⃗Bdt,F⃗BA=dp⃗Adt\vec{F}_{AB} = \dfrac{d\vec{p}_B}{dt}, \qquad \vec{F}_{BA} = \dfrac{d\vec{p}_A}{dt}

By Newton's third law, F⃗AB=−F⃗BA\vec{F}_{AB} = -\vec{F}_{BA}, so:

dp⃗Bdt=−dp⃗Adt\dfrac{d\vec{p}_B}{dt} = -\dfrac{d\vec{p}_A}{dt}

dp⃗Adt+dp⃗Bdt=0\dfrac{d\vec{p}_A}{dt} + \dfrac{d\vec{p}_B}{dt} = 0

ddt(p⃗A+p⃗B)=0⇒p⃗A+p⃗B=constant\dfrac{d}{dt}(\vec{p}_A + \vec{p}_B) = 0 \quad\Rightarrow\quad \vec{p}_A + \vec{p}_B = \text{constant}

So the total momentum of the system is conserved, as long as no external force acts.

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.