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Q.Calculate the resistivity of the material of the wire of length 2.0 m, diameter 1.0 mm having 50 ohm resistance.

Jammu Kashmir JkboseJKBOSE Class 12 Annual Regular Examination 2018Subjective· 2mImportance★★★★★
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Using ρ=RA/L\rho = RA/L with the wire's cross-sectional area found from its diameter, the resistivity works out to about 1.96×10−5 Ω m1.96\times10^{-5}\ \Omega\,\text{m}.

Given: length L=2.0L = 2.0 m, diameter d=1.0d = 1.0 mm =1.0×10−3= 1.0\times10^{-3} m (radius r=0.5×10−3r = 0.5\times10^{-3} m), resistance R=50 ΩR = 50\ \Omega.

Cross-sectional area:

A=πr2=π(0.5×10−3)2=π×0.25×10−6=7.854×10−7 m2A = \pi r^2 = \pi (0.5\times10^{-3})^2 = \pi \times 0.25\times10^{-6} = 7.854\times10^{-7}\ \text{m}^2

From R=ρL/AR = \rho L/A, the resistivity is: …

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