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Q.A wire of resistance 5 ohm is stretched to double its original length, what is its new resistance?

Jammu Kashmir JkboseJKBOSE Class 12 Annual Regular Examination 2026Subjective· 2mImportance★★★★★
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When a wire is stretched, its volume stays constant, so resistance scales as the square of the length ratio: doubling the length makes the resistance 4 times larger, i.e. 20 Ω20\ \Omega.

Concept. Resistance of a wire is R=ρlAR = \rho \dfrac{l}{A}, where ρ\rho is resistivity (a material property, unchanged by stretching), ll is length, and AA is cross-sectional area.

Constant volume on stretching. Since the wire's material volume V=AlV = A l does not change when it is stretched (it only becomes thinner and longer),

Al=A′l′=V  ⟹  A′=Vl′A l = A' l' = V \implies A' = \frac{V}{l'}

Expressing R in terms of volume. Multiply and divide RR by ll:

R=ρlA=ρl⋅lAl=ρl2VR = \rho\frac{l}{A} = \rho\frac{l \cdot l}{Al} = \frac{\rho l^2}{V} …

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