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Q.A wire of 5 ohm is stretched to double its original length. Calculate its new resistance.

Jammu Kashmir JkboseJKBOSE Class 12 Annual Regular Examination 2019Subjective· 3mImportance★★★★★
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When a wire is stretched, its volume stays constant, so R∝L2R\propto L^2; doubling the length quadruples the resistance.

Original resistance R=ρL/A=5 ΩR=\rho L/A=5\ \Omega.

When the wire is stretched to double its length (L′=2LL'=2L), its volume V=ALV=AL stays constant (no material is added or removed), so the new area A′A' satisfies

A′×2L=A×L⇒A′=A2A'\times 2L=A\times L \Rightarrow A'=\frac{A}{2} …

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