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Q.State Faraday's law of electromagnetic induction. Find the mutual inductance between two long co-axial solenoids. OR Define reactance and impedance in A.C. circuits. Derive expression for instantaneous current in a series L-C-R circuit if connected to an alternating emf.

Jharkhand JacJAC Intermediate Board 2019Subjective· 5mImportance★★★★★
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Faraday's law relates induced EMF to the rate of change of flux; for two coaxial solenoids, the mutual inductance is found by computing the flux the outer solenoid's field produces through the inner solenoid's turns, per unit current.

Faraday's law of electromagnetic induction: Whenever the magnetic flux ΦB\Phi_B linked with a circuit changes with time, an EMF is induced in the circuit, given by

ε=−dΦBdt\varepsilon = -\frac{d\Phi_B}{dt}

The negative sign (Lenz's law) indicates that the induced EMF opposes the change in flux that produces it.

Mutual inductance of two long coaxial solenoids: Consider two long solenoids of the same length ll, wound coaxially - an inner solenoid S1S_1 of radius r1r_1 with n1n_1 turns per unit length, and an outer solenoid S2S_2 of radius r2>r1r_2 > r_1 with n2n_2 turns per unit length, wound around S1S_1.

Let a current I2I_2 flow in the outer solenoid S2S_2. The magnetic field inside a long solenoid is uniform and given by

B2=μ0n2I2B_2 = \mu_0 n_2 I_2

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