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Physics · Ch 1 — Electric Charges and Fields

Forces Between Multiple Charges

1.6

Forces Between Multiple Charges

The Principle of Superposition

Coulomb’s law tells us the force between two isolated charges. But what happens when a charge is surrounded by many others? The answer comes from the principle of superposition, which is experimentally verified:

The total electrostatic force on any one charge due to a system of other charges is the vector sum of the individual Coulomb forces exerted by each of the other charges, taken one at a time. The presence of other charges does not alter the force between any given pair.

This means forces of electrostatic origin add just like mechanical forces — using the parallelogram law of vector addition.


Force on a Charge in a System of Three Charges

Consider three point charges q1q_1, q2q_2, and q3q_3 in vacuum. To find the net force F1\mathbf{F}_1 on q1q_1:

  1. Force due to q2q_2 alone (even though q3q_3 is present):

F12=14πε0q1q2r122r^12\mathbf{F}_{12} = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r_{12}^2} \hat{\mathbf{r}}_{12}

where r12r_{12} is the distance between q1q_1 and q2q_2, and r^12\hat{\mathbf{r}}_{12} is the unit vector pointing from q2q_2 to q1q_1.

  1. Force due to q3q_3 alone:

F13=14πε0q1q3r132r^13\mathbf{F}_{13} = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_3}{r_{13}^2} \hat{\mathbf{r}}_{13}

  1. Total force on q1q_1 is the vector sum:

F1=F12+F13\mathbf{F}_1 = \mathbf{F}_{12} + \mathbf{F}_{13}


Generalisation to nn Charges

For a system of nn stationary charges q1,q2,…,qnq_1, q_2, \dots, q_n, the total force on q1q_1 due to all others is:

F1=F12+F13+⋯+F1n\mathbf{F}_1 = \mathbf{F}_{12} + \mathbf{F}_{13} + \dots + \mathbf{F}_{1n}

Using Coulomb’s law for each pair:

F1=14πε0[q1q2r122r^12+q1q3r132r^13+⋯+q1qnr1n2r^1n]\mathbf{F}_1 = \frac{1}{4\pi\varepsilon_0} \left[ \frac{q_1 q_2}{r_{12}^2} \hat{\mathbf{r}}_{12} + \frac{q_1 q_3}{r_{13}^2} \hat{\mathbf{r}}_{13} + \dots + \frac{q_1 q_n}{r_{1n}^2} \hat{\mathbf{r}}_{1n} \right]

This can be written compactly as:

F1=q14πε0∑i=2nqir1i2r^1i\boxed{\mathbf{F}_1 = \frac{q_1}{4\pi\varepsilon_0} \sum_{i=2}^{n} \frac{q_i}{r_{1i}^2} \hat{\mathbf{r}}_{1i}}

Here:

  • r1ir_{1i} = distance between q1q_1 and qiq_i
  • r^1i\hat{\mathbf{r}}_{1i} = unit vector pointing from qiq_i to q1q_1

The vector sum is performed using the parallelogram law. This principle, together with Coulomb’s law, forms the foundation of all electrostatics.


Worked Example: Three Equal Charges at Vertices of an Equilateral Triangle

Setup: Three charges q1=q2=q3=qq_1 = q_2 = q_3 = q at vertices of an equilateral triangle of side ll. A charge QQ (same sign as qq) is placed at the centroid O.

Step 1 – Geometry:

Height of triangle AD=32lAD = \frac{\sqrt{3}}{2} l.

Distance from vertex to centroid: AO=23AD=l3AO = \frac{2}{3} AD = \frac{l}{\sqrt{3}}. By symmetry, AO=BO=COAO = BO = CO.

Step 2 – Forces on QQ:

Each force has magnitude:

F=14πε0Qq(l/3)2=34πε0Qql2F = \frac{1}{4\pi\varepsilon_0} \frac{Qq}{(l/\sqrt{3})^2} = \frac{3}{4\pi\varepsilon_0} \frac{Qq}{l^2}

Directions:

  • F1\mathbf{F}_1 from AA: along AOAO
  • F2\mathbf{F}_2 from BB: along BOBO
  • F3\mathbf{F}_3 from CC: along COCO

Step 3 – Vector addition:

F2\mathbf{F}_2 and F3\mathbf{F}_3 have equal magnitude and are symmetrically placed. Their resultant points along OAOA (opposite to F1\mathbf{F}_1) with magnitude FF.

Thus:

Fnet=F1+(resultant of F2,F3)=Fr^−Fr^=0\mathbf{F}_{\text{net}} = \mathbf{F}_1 + (\text{resultant of } \mathbf{F}_2, \mathbf{F}_3) = F \hat{\mathbf{r}} - F \hat{\mathbf{r}} = 0

where r^\hat{\mathbf{r}} is the unit vector along OAOA.

Result: The net force on QQ is zero. This is also clear by symmetry — rotating the system by 60∘60^\circ would not change the configuration.


Worked Example: Two +q+q and One −q-q at Triangle Vertices

Setup: Charges +q+q at A and B, −q-q at C, forming an equilateral triangle of side ll.

Step 1 – Magnitude of each pair force:

For any pair, the Coulomb force magnitude is the same:

F=14πε0q2l2F = \frac{1}{4\pi\varepsilon_0} \frac{q^2}{l^2}

Step 2 – Force on +q+q at A:

  • FAB\mathbf{F}_{AB} (repulsion from B) acts along BA
  • FAC\mathbf{F}_{AC} (attraction toward C) acts along AC …
Figure 1.5A system of (a) three charges (b) multiple charges.
Fig. 1.5 — A system of (a) three charges (b) multiple charges.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What the Figure Shows

The figure has two panels, (a) and (b), both illustrating the principle of superposition for electrostatic forces.

Panel (a) shows a system of three charges q1q_1, q2q_2, q3q_3 placed at different points in space. An origin OO is marked, and each charge has a position vector: r1\mathbf{r}_1, r2\mathbf{r}_2, r3\mathbf{r}_3 from OO. Dashed lines connect q1q_1 to q2q_2 and q1q_1 to q3q_3, labelled as separation vectors r12\mathbf{r}_{12} (from q1q_1 to q2q_2) and r13\mathbf{r}_{13} (from q1q_1 to q3q_3). Unit vectors r^12\hat{r}_{12} and r^13\hat{r}_{13} are drawn pointing toward q1q_1 (i.e., along the direction from the other charge to q1q_1). The forces F12\mathbf{F}_{12} (due to q2q_2) and F13\mathbf{F}_{13} (due to q3q_3) acting on q1q_1 are shown as arrows. A dashed parallelogram is constructed with F12\mathbf{F}_{12} and F13\mathbf{F}_{13} as adjacent sides, and the diagonal gives the resultant force F1\mathbf{F}_1 on q1q_1.

Panel (b) generalises to multiple charges — five charges q1,q2,q3,q4,q5q_1, q_2, q_3, q_4, q_5 are shown, with origin OO at the lower left. Solid spokes radiate from q1q_1 to each of the other charges. The forces F21,F31,F41,F51\mathbf{F}_{21}, \mathbf{F}_{31}, \mathbf{F}_{41}, \mathbf{F}_{51} on q1q_1 (each pointing away from its source charge) are drawn. A dashed head-to-tail chain of these force vectors is added, and the final vector from the tail of the first to the head of the last gives the resultant F1\mathbf{F}_1.

Physical Idea Taught

The figure teaches that the net electrostatic force on a charge due to many other charges is the vector sum of the individual Coulomb forces, each calculated as if the other charges were absent. This is the principle of superposition. The parallelogram law (panel a) and head-to-tail addition (panel b) are geometric ways to perform this vector sum. The key insight: forces from different charges do not interfere with each other — they simply add as vectors.

Key Formula Developed

The textbook uses this figure to derive the general expression for the force on charge q1q_1 due to n−1n-1 other charges q2,q3,…,qnq_2, q_3, \dots, q_n:

F1=F12+F13+⋯+F1n=14πε0∑i=2nq1qir1i2r^1i\mathbf{F}_1 = \mathbf{F}_{12} + \mathbf{F}_{13} + \dots + \mathbf{F}_{1n} = \frac{1}{4\pi\varepsilon_0} \sum_{i=2}^{n} \frac{q_1 q_i}{r_{1i}^2} \hat{r}_{1i}

where:

  • F1i\mathbf{F}_{1i} is the force on q1q_1 due to qiq_i,
  • r1ir_{1i} is the distance between q1q_1 and qiq_i, …