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Question of 20
Q.

Calculate Mean, Median and Mode.

Class IntervalFrequency
0 - 104
10 - 207
20 - 3010
30 - 4014
40 - 508
50 - 605
60 - 702
Kerala DhseKerala DHSE Plus One Commerce Board 2020Subjective· 8mImportance★★★★★
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Mean = 32.6, Median ≈ 32.86, Mode = 34.

Given (N = 4+7+10+14+8+5+2 = 50):

ClassfMidpoint (x)fxCumulative freq (cf)
0–1045204
10–2071510511
20–30102525021
30–40143549035
40–5084536043
50–6055527548
60–7026513050
Total50Σfx = 1630

Mean = Σfx / N = 1630 / 50 = 32.6

Median: N/2 = 50/2 = 25. The cumulative frequency just reaches/exceeds 25 in the class 30–40 (cf jumps from 21 to 35), so the median class is 30–40.

Median = L + ((N/2 − cf) / f) × h, where L = 30, cf = 21, f = 14, h = 10

Median = 30 + ((25 − 21)/14) × 10 = 30 + (4/14) × 10 = 30 + 2.857 = 32.86 (approx.)

Mode: The highest frequency is 14, in the class 30–40, so the modal class is 30–40.

Mode = L + ((f1 − f0) / (2f1 − f0 − f2)) × h, where L = 30, f1 = 14, f0 = 10, f2 = 8, h = 10 …

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