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Q.(i) State Hess's Law of Constant Heat Summation.

(1)
(ii) Construct an enthalpy diagram (Born-Haber cycle) to calculate the lattice enthalpy of Na+Cl-(s). (3)
Kerala DhseKerala DHSE Plus One Board 2025Subjective· 4mImportance★★★★★
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Hess's law: enthalpy change is path-independent (one step or many). Born-Haber cycle expresses delta(f)H(NaCl) as sublimation + ionisation + (1/2) dissociation + electron gain + lattice enthalpy; rearrange to get U.

Enthalpy born haber cycle formation nacl lattice
Enthalpy born haber cycle formation nacl lattice
  1. Hess's Law of Constant Heat Summation: If a reaction takes place in several steps, the overall enthalpy change equals the sum of the enthalpy changes of the individual steps; equivalently, the enthalpy change is the same whichever route is taken between the same initial and final states (because H is a state function).
  2. Born-Haber cycle for NaCl(s): imagine forming NaCl from its elements by two routes and equate them. Route steps:
  1. Na(s) -> Na(g): sublimation enthalpy, delta(sub)H (+).
  2. Na(g) -> Na+(g) + e-: ionisation enthalpy, IE (+).
  3. (1/2)Cl2(g) -> Cl(g): (1/2) x bond dissociation enthalpy, (1/2)delta(diss)H (+).
  4. Cl(g) + e- -> Cl-(g): electron gain enthalpy, delta(eg)H (-).
  5. Na+(g) + Cl-(g) -> NaCl(s): lattice enthalpy, U (-). By Hess's law: …

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