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Worked Examples · Example 4

Q.Five years ago, average age of a family of five was 32 years. The family includes Mrs. and Mr. Rai, their son, daughter and daughter in law. Recently, The daughter, Priya moved out of the house after marriage, at the age of 30 years. Calculate the family's present average age.

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Compute the total age of all 5 members 5 years ago, age everyone forward by 5 years, remove Priya's current age, and re-divide by the remaining 4 members.

Average age =Sum of agesNumber of members= \dfrac{\text{Sum of ages}}{\text{Number of members}}; after nn years, each surviving member's age increases by nn, so the group's total age increases by n×(number of members)n \times (\text{number of members}).

  1. Five years ago, the family had 5 members (Mr. Rai, Mrs. Rai, son, daughter, daughter-in-law) with average age 32, so their total age then =32×5=160= 32 \times 5 = 160 years.
  2. In the 5 years since, each of these 5 people has aged by 5 years, so total age now (before anyone leaves) =160+5×5=160+25=185= 160 + 5\times 5 = 160+25 = 185 years. …

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