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Intext Questions · 2.2

Q.Can you store copper sulphate solutions in a zinc pot?

Madhya Pradesh MpbseTextbookSubjective· 2mImportance★★★★★
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Galvanic corrosion makes storing copper sulphate in a zinc pot impossible — zinc will displace copper from the solution, corroding the pot and contaminating the contents. The answer is no.

The Core Idea: Galvanic Corrosion and Reactivity

This question is about galvanic corrosion — an electrochemical process that occurs when two dissimilar metals are in contact in the presence of an electrolyte. Here, the zinc pot is one metal, the copper sulphate solution is the electrolyte, and the copper ions in solution act as the second "metal" (they'll plate out as solid copper).

The driving force is the reactivity series of metals. Zinc is more reactive than copper — it sits higher in the series. This means zinc has a stronger tendency to lose electrons (oxidise) compared to copper. When you put them together in an electrolyte, zinc will spontaneously give up electrons, and copper ions will grab them.

Zn+CuSO4→ZnSO4+Cu\text{Zn} + \text{CuSO}_4 \rightarrow \text{ZnSO}_4 + \text{Cu}

This is a single displacement reaction — and it's the reason your zinc pot would be destroyed.

Step-by-Step Breakdown

1. Identify the reactants and their nature

You have solid zinc (the pot) and an aqueous solution of copper sulphate (CuSO4\text{CuSO}_4). In solution, copper sulphate dissociates into Cu2+\text{Cu}^{2+} ions and SO42−\text{SO}_4^{2-} ions. The zinc metal is a solid electrode.

2. Compare electrode potentials

The standard reduction potentials tell the story:

  • Cu2++2e−→Cu\text{Cu}^{2+} + 2e^- \rightarrow \text{Cu}: E∘=+0.34 VE^\circ = +0.34\ \text{V}
  • Zn2++2e−→Zn\text{Zn}^{2+} + 2e^- \rightarrow \text{Zn}: E∘=−0.76 VE^\circ = -0.76\ \text{V}

Zinc has a much more negative reduction potential — it's far more willing to lose electrons (oxidise) than copper is. In electrochemical terms, zinc acts as the anode (oxidation site) and copper ions act as the cathode (reduction site).

Watch out

A common mistake is to think "both are metals, so nothing happens." But copper is in ionic form, not metallic — it's already dissolved and ready to accept electrons. The zinc pot is the sacrificial metal here.

3. Write the half-reactions

Oxidation at the zinc surface:

Zn(s)→Zn2+(aq)+2e−\text{Zn(s)} \rightarrow \text{Zn}^{2+}(\text{aq}) + 2e^-

Reduction of copper ions in solution:

Cu2+(aq)+2e−→Cu(s)\text{Cu}^{2+}(\text{aq}) + 2e^- \rightarrow \text{Cu(s)}

4. Combine to see the net effect

The electrons lost by zinc are immediately taken up by copper ions. The net reaction:

Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s)\text{Zn(s)} + \text{Cu}^{2+}(\text{aq}) \rightarrow \text{Zn}^{2+}(\text{aq}) + \text{Cu(s)}

This means:

  • Zinc atoms leave the pot surface and go into solution as Zn2+\text{Zn}^{2+} ions — the pot corrodes.
  • Copper ions come out of solution and deposit as solid copper metal — you'll see a reddish-brown coating on the pot. …

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