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Exercises · Q12
Q.

200 people are classified by whether they were vaccinated and whether they contracted a disease, as shown. Compute the chi-square statistic and comment on the strength of any association.

Contracted diseaseNo diseaseTotal
Vaccinated1090100
Not vaccinated4060100
Total50150200
Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
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Step 1 — Expected frequencies, Eij=RiCj/NE_{ij} = R_i C_j / N, N=200N = 200. Row totals both 100; columns 50 (disease), 150 (no disease).

E(Vacc, Disease)=100×50200=25,E(Vacc, No disease)=100×150200=75E(\text{Vacc, Disease}) = \dfrac{100 \times 50}{200} = 25, \qquad E(\text{Vacc, No disease}) = \dfrac{100 \times 150}{200} = 75

E(Not vacc, Disease)=100×50200=25,E(Not vacc, No disease)=100×150200=75E(\text{Not vacc, Disease}) = \dfrac{100 \times 50}{200} = 25, \qquad E(\text{Not vacc, No disease}) = \dfrac{100 \times 150}{200} = 75

Step 2 — Tabulate (O−E)2/E(O-E)^2/E.

CellOOEEO−EO-E(O−E)2(O-E)^2(O−E)2/E(O-E)^2/E
Vacc, Disease1025−15225225/25=9225/25 = 9
Vacc, No disease907515225225/75=3225/75 = 3
Not vacc, Disease402515225225/25=9225/25 = 9
Not vacc, No disease6075−15225225/75=3225/75 = 3
Total24

Step 3 — Sum.

χ2=9+3+9+3=24\chi^2 = 9 + 3 + 9 + 3 = 24 …

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