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Worked Examples · Example 7
Q.

In a survey of 100 people classified by literacy and employment status, the observed frequencies are shown. Compute the chi-square statistic and state what it says about the two attributes.

EmployedUnemployedTotal
Literate302050
Illiterate302050
Total6040100
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Step 1 — Compute the expected frequencies, Eij=RiCj/NE_{ij} = R_i C_j / N, N=100N = 100. Row totals both 50; column totals 60 (Employed), 40 (Unemployed).

E(Literate, Employed)=50×60100=30,E(Literate, Unemployed)=50×40100=20E(\text{Literate, Employed}) = \dfrac{50 \times 60}{100} = 30, \qquad E(\text{Literate, Unemployed}) = \dfrac{50 \times 40}{100} = 20

E(Illiterate, Employed)=50×60100=30,E(Illiterate, Unemployed)=50×40100=20E(\text{Illiterate, Employed}) = \dfrac{50 \times 60}{100} = 30, \qquad E(\text{Illiterate, Unemployed}) = \dfrac{50 \times 40}{100} = 20

Step 2 — Compare observed with expected.

CellOOEEO−EO-E(O−E)2/E(O-E)^2/E
Literate, Employed303000
Literate, Unemployed202000
Illiterate, Employed303000
Illiterate, Unemployed202000
Total0

Step 3 — Sum.

χ2=0+0+0+0=0\chi^2 = 0 + 0 + 0 + 0 = 0 …

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