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Mathematics and Statistics · Ch 3 — Complex Numbers

Cube Roots of Unity

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Cube Roots of Unity

The equation z3=1z^{3}=1 has three solutions in C\mathbb{C} — the cube roots of unity — with elegant properties used throughout algebra.

Finding the three roots

Solve z3=1z^{3}=1, i.e. z3−1=0z^{3}-1=0. Factor as a difference:

z3−1=(z−1)(z2+z+1)=0.z^{3}-1=(z-1)(z^{2}+z+1)=0.

So either z=1z=1, or z2+z+1=0z^{2}+z+1=0, whose roots (by the quadratic formula) are

z=−1±1−42=−1±−32=−1±i32.z=\frac{-1\pm\sqrt{1-4}}{2}=\frac{-1\pm\sqrt{-3}}{2}=\frac{-1\pm i\sqrt{3}}{2}.

The three cube roots of unity are therefore

1,ω=−1+i32,ω2=−1−i32.1,\qquad \omega=\frac{-1+i\sqrt3}{2},\qquad \omega^{2}=\frac{-1-i\sqrt3}{2}.

The two complex roots are conjugates of each other, and either one is denoted ω\omega (omega); its square is the other.

The two key properties

Properties of ω\omega

ω3=1and1+ω+ω2=0.\omega^{3}=1\qquad\text{and}\qquad 1+\omega+\omega^{2}=0.

The first says ω\omega is a genuine cube root of 11 (so any power of ω\omega reduces mod 33: ω4=ω, ω5=ω2\omega^{4}=\omega,\ \omega^{5}=\omega^{2}, etc.). The second is just the coefficient relation from z2+z+1=0z^{2}+z+1=0; it lets you replace 1+ω1+\omega by −ω2-\omega^{2}, or ω+ω2\omega+\omega^{2} by −1-1, to simplify expressions. …

Definition 1Cube roots of unity

The three solutions of z3=1z^{3}=1: namely $1,\ \omega=\tfrac{-1+i\sqrt3}{2},\ \omega^{2}=\tfrac …

Definition 2Properties of $\omega$

ω3=1\omega^{3}=1 and 1+ω+ω2=01+\omega+\omega^{2}=0. Hence 1+ω=−ω21+\omega=-\omega^{2}, 1+ω2=−ω1+\omega^{2}=-\omega, $\om …