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Worked Examples · Example 3

Q.Solve the combined inequation −3<2x+1≤5-3<2x+1\le 5 for x∈Rx\in\mathbb{R} and write the solution in interval form.

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✓ Free question

A double inequation is two conditions at once; apply each operation to all three parts.

Subtract 11 throughout:

−3−1<2x+1−1≤5−1 ⇒ −4<2x≤4.-3-1<2x+1-1\le 5-1\ \Rightarrow\ -4<2x\le 4.

Divide throughout by the positive 22 (signs unchanged):

−2<x≤2.-2<x\le 2.

The left end is strict (<<, open) and the right end is weak (≤\le, closed), so the solution set is (−2,2](-2,2].

Check (independent verification): the two boundaries must behave correctly. At x=−2x=-2: 2(−2)+1=−32(-2)+1=-3, and −3<−3-3<-3 is false ✓ excluded. At x=2x=2: 2(2)+1=52(2)+1=5, and 5≤55\le5 is true ✓ included. A middle value x=0x=0: −3<1≤5-3<1\le5 ✓.

✓Final answer

−2<x≤2-2<x\le 2, i.e. x∈(−2,2]x\in(-2,2]

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