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Worked Examples · Example 1

Q.How many 33-digit numbers can be formed using the digits 1,2,3,4,51, 2, 3, 4, 5 if no digit is repeated?

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✓ Free question

A 33-digit number has three places to fill, and by the multiplication principle the total is the product of the choices at each place.

  • Hundreds place: any of the 55 digits ⇒5\Rightarrow 5 ways.
  • Tens place: any digit except the one already used ⇒4\Rightarrow 4 ways.
  • Units place: any digit except the two already used ⇒3\Rightarrow 3 ways.

5×4×3=60.5 \times 4 \times 3 = 60.

Independent check (nPr^{n}P_{r}): this is exactly arranging 33 of 55 distinct digits in order, 5P3=5!2!=1202=60^{5}P_{3} = \dfrac{5!}{2!} = \dfrac{120}{2} = 60 — matches.

✓Final answer

6060 three-digit numbers can be formed

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