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Worked Examples · Example 2

Q.A student can travel from city A to city B by 33 bus services or 22 train services, and from B to C by 44 bus services or 11 flight. In how many ways can the student travel from A to C via B?

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56% · 10/18 Questions
✓ Free question

The journey combines the addition principle (choices within a leg are alternatives) with the multiplication principle (the two legs happen one after the other).

  • A to B: 33 buses or 22 trains ⇒3+2=5\Rightarrow 3 + 2 = 5 ways.
  • B to C: 44 buses or 11 flight ⇒4+1=5\Rightarrow 4 + 1 = 5 ways.

The trip A→\toB and B→\toC is completed only when both legs are done, so multiply:

5×5=25.5 \times 5 = 25.

Independent check (list the leg-types): each of the 55 ways for the first leg can pair with each of the 55 ways for the second, forming a 5×55 \times 5 grid of 2525 distinct routes.

✓Final answer

The student can travel in 2525 ways

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