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Mathematics and Statistics · Ch 16 — Probability

Addition Theorem of Probability

4

Addition Theorem of Probability

The addition theorem gives the probability that at least one of two events occurs — the probability of the union A∪BA \cup B.

Note

Addition theorem (general)

For any two events AA and BB of the same sample space,

P(A∪B)=P(A)+P(B)−P(A∩B).P(A \cup B) = P(A) + P(B) - P(A \cap B).

The subtraction of P(A∩B)P(A \cap B) is essential: outcomes common to both AA and BB are counted once in P(A)P(A) and again in P(B)P(B), so they would be double-counted unless we remove them once. (This is exactly the inclusion–exclusion idea for the sizes of sets.)

Note

Addition theorem for mutually exclusive events

If AA and BB are mutually exclusive then A∩B=∅A \cap B = \varnothing, so P(A∩B)=0P(A \cap B) = 0 and the theorem simplifies to

P(A∪B)=P(A)+P(B).P(A \cup B) = P(A) + P(B).

More generally, for mutually exclusive events A1,A2,…,AkA_1, A_2, \ldots, A_k,

P(A1∪A2∪⋯∪Ak)=P(A1)+P(A2)+⋯+P(Ak).P(A_1 \cup A_2 \cup \cdots \cup A_k) = P(A_1) + P(A_2) + \cdots + P(A_k).

Example. Draw one card from a pack. Let AA = "the card is a heart" and BB = "the card is a king". Then P(A)=1352P(A) = \dfrac{13}{52}, P(B)=452P(B) = \dfrac{4}{52}, and A∩BA \cap B = "the king of hearts", a single card, so P(A∩B)=152P(A \cap B) = \dfrac{1}{52}. The probability the card is a heart or a king is …

Definition 10Addition theorem

P(A∪B)=P(A)+P(B)−P(A∩B)P(A \cup B) = P(A) + P(B) - P(A \cap B) for any two events; it reduces to P(A)+P(B)P(A) + P(B) when the events are …