Mathematics · Ch 6 — Circle
Tangent to a Circle
Tangent to a Circle
Tangent to a Circle
Definition. When a line meets a circle at two coincident points (rather than two distinct points, or none), it is called a tangent to the circle, and the single point where they meet is the point of contact.
Deriving the tangent at a point on the standard circle. Let the circle be , centred at , and let be a point on it. The slope of the radius is (for ). A key geometric fact about circles is that the tangent at any point is always perpendicular to the radius drawn to that point. So the tangent's slope satisfies
(the negative reciprocal of the radius's slope). Using the point-slope form of a line through with this slope:
Multiplying through by and rearranging:
Since lies on the circle, , so this simplifies to
The equation of the tangent to the circle at the point on it is .
Extending to the general-form circle. Following the same method for , the tangent at a point on this circle works out to
A handy way to remember this: starting from the circle's own equation, replace by , by , by , and by — a substitution rule that works for the tangent at any point on a circle written in this general form.
Tangent in parametric form. If the point of contact is written using the circle's own parameter as , substituting , into gives
Solved Example 2 — show is a tangent to ; find the point of contact
Step 1 — substitute the line into the circle. From , . Substituting into :
Multiplying through by : , i.e.
Step 2 — check the discriminant. This factors as — a repeated root, . A line meeting a circle in a repeated root meets it at only one (coincident) point, which is exactly the definition of a tangent — so the line is indeed tangent to the circle. …
What this figure shows. A circle centred at the origin O with a point P(x1, y1) on it, the radius OP drawn, and a tangent line drawn through P perpendicular to OP -- the picture used to find the tangent's slope as the negative reciprocal of OP's slope. …
Worked out. Substitutes the line into the circle to get a quadratic in x, shows its discriminant is zero (equal roots, so a single point of intersection), and back-substitutes that repeated root to get the point of contact. …
Worked out. Applies the general-form tangent formula xx1+yy1+g(x+x1)+f(y+y1)+c=0 directly with the given point and the g,f,c read off the circle's equation, then simplifies. …