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Mathematics · Ch 6 — Circle

Tangent to a Circle

6.3.1

Tangent to a Circle

Tangent to a Circle

Definition. When a line meets a circle at two coincident points (rather than two distinct points, or none), it is called a tangent to the circle, and the single point where they meet is the point of contact.

Deriving the tangent at a point on the standard circle. Let the circle be x2+y2=r2x^2+y^2=r^2, centred at O(0,0)O(0,0), and let P(x1,y1)P(x_1,y_1) be a point on it. The slope of the radius OPOP is y1x1\dfrac{y_1}{x_1} (for x1≠0x_1\neq0). A key geometric fact about circles is that the tangent at any point is always perpendicular to the radius drawn to that point. So the tangent's slope mm satisfies

m=−x1y1m=-\frac{x_1}{y_1}

(the negative reciprocal of the radius's slope). Using the point-slope form of a line through P(x1,y1)P(x_1,y_1) with this slope:

y−y1=−x1y1(x−x1)y-y_1=-\frac{x_1}{y_1}(x-x_1)

Multiplying through by y1y_1 and rearranging:

yy1−y12=−xx1+x12  ⟹  xx1+yy1=x12+y12yy_1-y_1^2=-xx_1+x_1^2 \implies xx_1+yy_1=x_1^2+y_1^2

Since P(x1,y1)P(x_1,y_1) lies on the circle, x12+y12=r2x_1^2+y_1^2=r^2, so this simplifies to

xx1+yy1=r2xx_1+yy_1=r^2

The equation of the tangent to the circle x2+y2=r2x^2+y^2=r^2 at the point (x1,y1)(x_1,y_1) on it is xx1+yy1=r2xx_1+yy_1=r^2.

Extending to the general-form circle. Following the same method for x2+y2+2gx+2fy+c=0x^2+y^2+2gx+2fy+c=0, the tangent at a point (x1,y1)(x_1,y_1) on this circle works out to

xx1+yy1+g(x+x1)+f(y+y1)+c=0xx_1+yy_1+g(x+x_1)+f(y+y_1)+c=0

A handy way to remember this: starting from the circle's own equation, replace x2x^2 by xx1xx_1, 2x2x by (x+x1)(x+x_1), y2y^2 by yy1yy_1, and 2y2y by (y+y1)(y+y_1) — a substitution rule that works for the tangent at any point on a circle written in this general form.

Tangent in parametric form. If the point of contact is written using the circle's own parameter as (rcos⁡θ1,rsin⁡θ1)(r\cos\theta_1, r\sin\theta_1), substituting x1=rcos⁡θ1x_1=r\cos\theta_1, y1=rsin⁡θ1y_1=r\sin\theta_1 into xx1+yy1=r2xx_1+yy_1=r^2 gives

xcos⁡θ1+ysin⁡θ1=rx\cos\theta_1+y\sin\theta_1=r

Solved Example 2 — show 3x−4y+15=03x-4y+15=0 is a tangent to x2+y2=9x^2+y^2=9; find the point of contact

Step 1 — substitute the line into the circle. From 3x−4y+15=03x-4y+15=0, y=3x+154y=\dfrac{3x+15}{4}. Substituting into x2+y2=9x^2+y^2=9:

x2+(3x+15)216=9x^2+\frac{(3x+15)^2}{16}=9

Multiplying through by 1616: 16x2+9x2+90x+225=14416x^2+9x^2+90x+225=144, i.e.

25x2+90x+81=025x^2+90x+81=0

Step 2 — check the discriminant. This factors as (5x+9)2=0(5x+9)^2=0 — a repeated root, x=−95x=-\dfrac95. A line meeting a circle in a repeated root meets it at only one (coincident) point, which is exactly the definition of a tangent — so the line is indeed tangent to the circle. …

Figure Fig.6.8Fig. 6.8 — tangent at a point on the standard circle

What this figure shows. A circle centred at the origin O with a point P(x1, y1) on it, the radius OP drawn, and a tangent line drawn through P perpendicular to OP -- the picture used to find the tangent's slope as the negative reciprocal of OP's slope. …

Misc Ex.2Show 3x-4y+15=0 is a tangent to x^2+y^2=9; find the point of contact

Worked out. Substitutes the line into the circle to get a quadratic in x, shows its discriminant is zero (equal roots, so a single point of intersection), and back-substitutes that repeated root to get the point of contact. …

Misc Ex.3Tangent to x^2+y^2-4x-6y-12=0 at (-1,-1)

Worked out. Applies the general-form tangent formula xx1+yy1+g(x+x1)+f(y+y1)+c=0 directly with the given point and the g,f,c read off the circle's equation, then simplifies. …