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Exercise 6.3 · Q30

Q.Write the parametric equations of the circle (x−3)2+(y+4)2=25(x-3)^2+(y+4)^2=25.

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✓ Free question

The equation (x−3)2+(y+4)2=25(x-3)^2+(y+4)^2=25 is already the centre-radius form with centre (3,−4)(3,-4) and radius 55. Applying x=h+rcos⁡θ, y=k+rsin⁡θx=h+r\cos\theta,\ y=k+r\sin\theta:

✓Final answer

x=3+5cos⁡θ,y=−4+5sin⁡θx=3+5\cos\theta,\quad y=-4+5\sin\theta.

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