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Miscellaneous Exercise 1 (MCQ) · Q158

Q.If −1+3 i=reiθ-1+\sqrt3\,i = re^{i\theta}, then θ=\theta = ................. . (A) −2π3-\dfrac{2\pi}{3} (B) π3\dfrac{\pi}{3} (C) −π3-\dfrac{\pi}{3} (D) 2π3\dfrac{2\pi}{3}

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For z=−1+sqrt3iz=-1+\\sqrt3i: ∣z∣=sqrt1+3=2|z|=\\sqrt{1+3}=2. Quadrant II: $\theta=\tan^{-1}\left(\dfrac{\sqrt3}{-1}\right)+\pi=-\dfrac{\pi}{3}+\pi=\df …

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