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Miscellaneous Exercise 1 (Subjective) · Q201

Q.Show that 1−2i3−4i+1+2i3+4i\dfrac{1-2i}{3-4i}+\dfrac{1+2i}{3+4i} is real.

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dfrac1−2i3−4i+dfrac1+2i3+4i=dfrac(1−2i)(3+4i)+(1+2i)(3−4i)(3−4i)(3+4i)\\dfrac{1-2i}{3-4i}+\\dfrac{1+2i}{3+4i}=\\dfrac{(1-2i)(3+4i)+(1+2i)(3-4i)}{(3-4i)(3+4i)}. Numerator: (1−2i)(3+4i)=3+4i−6i−8i2=3−2i+8=11−2i(1-2i)(3+4i)=3+4i-6i-8i^2=3-2i+8=11-2i, and (1+2i)(3−4i)=3−4i+6i−8i2=3+2i+8=11+2i(1+2i)(3-4i)=3-4i+6i-8i^2=3+2i+8=11+2i; adding gives 2222. Denominator: 9+16=259+16=25. So the …

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