Skip to content
Miscellaneous Exercise 1 (Subjective) · Q197

Q.Convert the complex number in polar form and also in exponential form : z=−6+2 iz = -6+\sqrt2\,i

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
95% · 197/208 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

For z=−6+2iz=-6+\sqrt2i: ∣z∣=36+2=38|z|=\sqrt{36+2}=\sqrt{38}. Quadrant II: θ=tan⁡−1(2−6)+π=π−tan⁡−126\theta=\tan^{-1}\left(\dfrac{\sqrt2}{-6}\right)+\pi=\pi-\tan^{-1}\dfrac{\sqrt2}{6}. Polar form: 38(cos⁡θ+isin⁡θ)\sqrt{38}(\cos\theta+i\sin\theta); exponential form: 38eiθ\sqrt{38}e^{i\theta}.

✓Final answer

∣z∣=38|z|=\sqrt{38}, $\t …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.