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Mathematics · Ch 7 — Conic Sections

Focal Distance and Latus Rectum of a Parabola

7.1.7

Focal Distance and Latus Rectum of a Parabola

Two of the most useful numerical facts about a parabola — its focal distance formula and its latus-rectum length — follow quickly from the standard equation.

1. Focal distance formula. Let P(x1,y1)P(x_1,y_1) be any point on y2=4axy^2=4ax, and let M=(−a,y1)M=(-a,y_1) be the foot of the perpendicular from PP to the directrix x+a=0x+a=0. By the very definition of the parabola, SP=PMSP=PM. Computing PMPM directly (it's a horizontal distance, since MM and PP share the yy-coordinate):

PM=(x1−(−a))2+(y1−y1)2=x1+a.PM = \sqrt{(x_1-(-a))^2+(y_1-y_1)^2} = x_1+a.

So the focal distance of any point P(x1,y1)P(x_1,y_1) on the parabola is simply

SP=x1+a=a+(abscissa of P).SP = x_1+a = a+(\text{abscissa of } P).

This is a genuinely useful shortcut: you never need the distance formula for a focal distance on a parabola — just add aa to the point's xx-coordinate.

2. Length of the latus rectum. The latus rectum is the focal chord LSL′LSL' perpendicular to the axis (section 7.1.4's definition, specialised to the parabola). By the curve's symmetry about the XX-axis, the two halves LSLS and L′SL'S are equal; call this common length ll. Since LL lies directly above the focus S=(a,0)S=(a,0), its coordinates are (a,l)(a,l).

Because LL lies on the parabola, it must satisfy y2=4axy^2=4ax:

l2=4a(a)=4a2  ⟹  l=±2a.l^2 = 4a(a) = 4a^2 \;\Longrightarrow\; l=\pm2a.

Since LL is taken in the upper half (first quadrant), l=2al=2a. So the length of the full latus rectum is

LSL′=2l=2(2a)=4a,LSL' = 2l = 2(2a) = 4a, …

Figure 7.7Latus rectum $LSL'$

What this figure shows. The focal chord LSL′LSL' perpendicular to the axis, with L,L′L,L' the two points where the parabola meets the vertical line through the focus. This figure gives the reader a concrete visual reference for the geometric configuration described in the surrounding text, tying the abstract statement to …

Misc 1.7-ActActivity: latus rectum of a parabola

Worked out. Two practice prompts finding the length and end points of the latus rectum of (1) x2=8yx^2=8y and (2) 5y2=16x5y^2=16x. Working through this worked example after reading the theory above helps consolidate the method before attempting the exercise questions that follow it in the textboo …