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Mathematics · Ch 7 — Conic Sections

Standard Equation of a Parabola

7.1.5

Standard Equation of a Parabola

Definition. A parabola is the locus of a point in the plane that is equidistant from a fixed point (the focus) and a fixed line (the directrix) — this is exactly the focus–directrix definition of section 7.1.3 with e=1e=1, since SP=PMSP=PM means the ratio SP/PMSP/PM is always 11.

Deriving the standard equation y2=4axy^2=4ax.

Let SS be the focus and dd the directrix. Draw SZSZ perpendicular to the directrix (so ZZ is the foot of that perpendicular, the point on dd closest to SS), and let OO be the midpoint of segment SZSZ. By the very definition of the parabola, this midpoint OO is itself equidistant from SS and from the directrix — so OO lies on the parabola. This makes OO a natural choice of origin.

Set up coordinates with:

  • OO as the origin,
  • the line OSOS as the XX-axis,
  • the line through OO perpendicular to OSOS as the YY-axis.

Let SZ=2aSZ = 2a (with a>0a>0). Since OO is the midpoint of SZSZ, the focus is S=(a,0)S=(a,0) and the foot of the perpendicular is Z=(−a,0)Z=(-a,0). The directrix, being the vertical line through ZZ, has equation x=−ax=-a, i.e. x+a=0x+a=0.

Now let P(x,y)P(x,y) be any point on the parabola, and let MM be the foot of the perpendicular from PP to the directrix; since the directrix is x=−ax=-a, we have M=(−a,y)M=(-a,y).

By the distance formula:

SP=(x−a)2+y2,PM=(x+a)2.SP=\sqrt{(x-a)^2+y^2},\qquad PM=\sqrt{(x+a)^2}.

The defining property SP=PMSP=PM (since e=1e=1) gives

(x−a)2+y2=(x+a)2.\sqrt{(x-a)^2+y^2}=\sqrt{(x+a)^2}.

Squaring both sides: …

Misc 1.5-ActActivity: parabola from focus and directrix

Worked out. Two practice prompts: find the equation of a parabola (1) with focus (2,0)(2,0) and directrix x+2=0x+2=0, and (2) with focus (−4,0)(-4,0) and directrix x=4x=4 — both solved by direct comparison with y2=±4axy^2=\pm4ax. …