Definition. A determinant of order 3 is a square arrangement of 9 elements enclosed between two vertical bars, arranged in 3 rows and 3 columns:
D=a11a21a31a12a22a32a13a23a33
Here aij denotes the element in the i-th row and j-th column. For instance a31 is the element in the 3rd row, 1st column. A determinant is usually named by a capital letter, or by Δ (delta). The rows are R1,R2,R3 and the columns C1,C2,C3 — e.g. the 2nd row is [a21a22a23] and the 3rd column is a13a23a33.
Expansion of a determinant
A 3×3 determinant can be expanded along any of its 3 rows or 3 columns — six expansions in all, and every one gives the same value (this is proved as Property 1 in §4.2). Expanding along the first row:
Notice the alternating +,−,+ signs, and that each 2×2 determinant is obtained by deleting the row and column of the multiplying element (this "leftover" 2×2 determinant is formally called a minor, defined in §4.1.3).
Worked Examples
Example (i). Evaluate 3−1−2−4−1−3521.
Step 1: Expand along row 1: D=3−1−321−(−4)−1−221+5−1−2−1−3.
Step 2: Evaluate each 2×2 piece: −1−321=(−1)(1)−(2)(−3)=−1+6=5; −1−221=(−1)(1)−(2)(−2)=−1+4=3; −1−2−1−3=(−1)(−3)−(−1)(−2)=3−2=1.
Step 3: Combine: D=3(5)+4(3)+5(1)=15+12+5.
D=32
Example (ii). Evaluate secθtanθ0tanθsecθ0001.
Step 1: The third column has only one non-zero entry (1 in row 3), so expand along the third column: D=1×secθtanθtanθsecθ (the sign is (−1)3+3=+1).
Step 2: Evaluate the 2×2 piece: sec2θ−tan2θ.
Step 3: Use the identity sec2θ−tan2θ=1.
D=1
Example (iii). Evaluate 2−i3−132−i−2102−i, where i=−1. …
Misc 4.1.2Worked Examples — evaluating three order-3 determinants
Worked out. Three worked expansions along the first row: a purely numeric 3×3 determinant, a 3×3 determinant of secθ/tanθ entries with a row of zeros that collapses quickly, and a 3×3 determinant with complex entries using i²=−1. …