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Miscellaneous Exercise 8 (I) · Q25

Q.Number of patients who visited cardiologists are 13, 17, 11, 15 in four days then standard deviation (approximately) is A) 5 patients B) 4 patients C) 10 patients D) 15 patients

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✓ Free question

Step 1: Mean =13+17+11+154=564=14=\dfrac{13+17+11+15}{4}=\dfrac{56}{4}=14.

Step 2: Deviations from mean: −1,3,−3,1-1,3,-3,1; squared: 1,9,9,11,9,9,1, summing to 2020.

Step 3: Var(X)=20/4=5\text{Var}(X)=20/4=5, so the rigorous S.D.=5≈2.24\text{S.D.}=\sqrt{5}\approx2.24 patients.

Step 4: None of the four printed options (5, 4, 10, 15 patients) matches this rigorously computed value of ≈2.24\approx2.24 patients — this looks like an error in the option set of this particular MCQ (the value 5 printed as option A actually equals the variance, not the S.D., which is a plausible explanation for how the option list was built).

✓Final answer

Rigorously, S.D. =5≈2.24=\sqrt{5}\approx2.24 patients. If forced to choose among the given options, A) 5 is the closest (it equals the variance) — flagged here honestly as a likely error in the printed option set, not a confidently matched choice.

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