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Miscellaneous Exercise 8 (II) · Q54
Q.

There are two companies U and V which manufacture cars. A sample of 40 cars each from these companies are taken and the average running life (in years) is recorded.

Life (in years)Company UCompany V
0-5514
5-10188
10-151718

Which company shows greater consistency?

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
98% · 54/55 Questions
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Step 1 — Company U: mid-values 2.5, 7.5, 12.5 with frequencies 5, 18, 17 (N=40N=40). ∑fixi=12.5+135+212.5=360\sum f_ix_i = 12.5+135+212.5=360, mean =360/40=9=360/40=9. ∑fixi2=31.25+1012.5+2656.25=3700\sum f_ix_i^2 = 31.25+1012.5+2656.25=3700. Var=3700/40−81=92.5−81=11.5\text{Var}=3700/40-81=92.5-81=11.5, so σU≈3.39\sigma_U\approx3.39.

Step 2: C.V.U=100×3.39/9≈37.68%\text{C.V.}_U = 100\times3.39/9\approx37.68\%.

Step 3 — Company V: same mid-values with frequencies 14, 8, 18 (N=40N=40). ∑fixi=35+60+225=320\sum f_ix_i = 35+60+225=320, mean =320/40=8=320/40=8. ∑fixi2=87.5+450+2812.5=3350\sum f_ix_i^2 = 87.5+450+2812.5=3350. Var=3350/40−64=83.75−64=19.75\text{Var}=3350/40-64=83.75-64=19.75, so σV≈4.44\sigma_V\approx4.44. …

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