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Miscellaneous Exercise 8 (II) · Q45

Q.The mean and S.D. of a group of 50 observations are 40 and 5 respectively. If two more observations 60 and 72 are added to the set, find the mean and S.D. of 52 items.

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Step 1: Original n=50n=50, mean =40=40, so original total =50×40=2000=50\times40=2000. Adding 60 and 72: new total =2000+60+72=2132=2000+60+72=2132; new n=52n=52, so new mean =2132/52=41=2132/52=41.

Step 2: Original S.D. =5=5, so original Var =25=25, giving original ∑x2=50(25+1600)=81250\sum x^2 = 50(25+1600)=81250. Adding the two new observations: new ∑x2=81250+602+722=81250+3600+5184=90034\sum x^2 = 81250+60^2+72^2=81250+3600+5184=90034. …

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